Question

当用户在同一页面上提交电子邮件时，我一直在尝试设置＆＃34;谢谢＆＃34; 消息，以便消息显示在提交表单下方以我选择的颜色。

但是，到目前为止，我的代码只提交了电子邮件而没有感谢您消息，似乎没有回复带有反馈ID的p标签。

那么如何修改我的代码，以便在提交电子邮件时将ID为#feedback的p-tag显示为感谢信息？

$email = $_REQUEST['email'] ;

require("C:/inetpub/folder/PHPMailer/PHPMailerAutoload.php");

$mail = new PHPMailer();

$mail->IsSMTP();
$mail->Host = "smtp.comcast.net"; 
$mail->SMTPAuth = true; 
$mail->Username = "username@comcast.net"; // SMTP username
$mail->Password = "**********"; // SMTP password
$mail->SMTPSecure = 'TLS';// Enable TLS encryption, `ssl` also accepted
$mail->Port = 25;                                   
$mail->From = $email;
$mail->setFrom('$email', 'Guest');
$mail->addAddress('admin@mydomain.com', 'Support');
$mail->WordWrap = 50;
$mail->IsHTML(true);
$mail->Subject = "A new member wishes to be added";
$mail->Body = $email;
$mail->AltBody = $email;


$mail2 = new PHPMailer();
$mail2->IsSMTP();
$mail2->Host = "smtp.comcast.net"; 
$mail2->SMTPAuth = true; 
$mail2->Username = "username@comcast.net"; // SMTP username
$mail2->Password = "*********"; // SMTP password
$mail2->SMTPSecure = 'TLS';                           
$mail2->Port = 25;                                 
$mail2->setFrom('support@mydomain.com', 'Support');
$mail2->AddAddress("$email");
$mail2->addReplyTo('support@mydomain.com');
$mail2->WordWrap = 50;

mail($to, $subject, $message, $headers);

$mail2->Subject = "Thanks for signing up";
$headers = "From: " . strip_tags($_POST['admin@mydomain.com']) . "\r\n";
$headers .= "Reply-To: ". strip_tags($_POST['loo@mydomain.com']) . "\r\n";
$headers .= "MIME-Version: 1.0\r\n";
$headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n";


$message = '<html><body>';
$mail2->IsHTML(true);
$message .= '<p style="font-size:16px; color:#000; font-weight:bold;">Welcome,</p> ';
$message .= "<p style='line-height:1.6; color:#666; font-size:16px;'>You have been added to.</p> " ;
$message .= "</body></html>";
$mail2->Body = $message;
$mail2->AltBody = $message;

if (!$mail2->Send()) {

$feedback = 'Thanks for the email';

}
if (!$mail->Send()) {

$feedback = 'Thanks for the email';

}

?>

html：

<div class="guestlist">
<form action="?" method="post">
<input type="email" title="Enter Email Address" class="emailaddress" name="email" placeholder="Enter your Email Address" />
<button class="button" title="Submit Email to Guestlist"  name="submit" value="Submit" type='submit'>Join</button>
 <p id="feedback"> <?php echo $feedback; ?> </p>
  </form>
  </div>   
  </div>

Answer 1

您应该阅读PHP手册，以便基本了解如何解释和编译代码以及将哪些内容作为输出发送。

用户首先看到feedback变量为空的html;
用户点击按钮，东西被发送到服务器。 feedback变量现在包含一个值，但HTML页面不会重新加载，因此保持不变。

重新加载发送feedback的HTML页面或使用ajax并听取答案：

$("button[name=submit]").on("click",function(){
    type: "post",
    url: mail.php,
    success: function(serverResponse){
        $("#feedback").html(serverResponse);
    }
});

在这种情况下，您应该echo $feedback;

Answer 2

如果电子邮件成功，我不会看到如何设置$反馈。

if (!$mail2->Send()) {

$feedback = 'Thanks for the email';

}
if (!$mail->Send()) {

$feedback = 'Thanks for the email';

}

对我说如果不成功。

设计一个PHP＆＃34;谢谢你＆＃34;消息，因此它显示在同一页面的底部

2 个答案: