Android应用程序在onActivityResult方法中崩溃

时间:2015-07-02 19:37:23

标签: java android crash

我的Android应用程序在案例2崩溃,案例3不起作用(不要从相机拍照)。案例0和案例1运作良好。

onClick方法:

           public void onClick(View v) {
                if(position == 0 && menuID == mFrameID1)
                {
                    Intent pickPhoto = new Intent(Intent.ACTION_PICK,
                            android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
                    startActivityForResult(pickPhoto , 1);//pick photo from gallery
                }
                else if(position == 1 && menuID == mFrameID1)
                {
                    Intent takePicture = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
                    startActivityForResult(takePicture, 0);//capture from camera
                }
               else if(position == 0 && menuID == mFrameID2)
                {
                    Intent pickPhoto = new Intent(Intent.ACTION_PICK,
                            android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
                    startActivityForResult(pickPhoto , 2);//pick photo from gallery
                }
                else if(position == 1 && menuID == mFrameID2)
                {
                    Intent takePicture = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
                    startActivityForResult(takePicture, 3);//capture from camera
                }
        }

onActivityResult方法

protected void onActivityResult(int requestCode, int resultCode, Intent imageReturnedIntent) {
        super.onActivityResult(requestCode, resultCode, imageReturnedIntent);

    switch(requestCode) {
        case 0:
            if(resultCode == RESULT_OK){
                Bitmap photo = (Bitmap) imageReturnedIntent.getExtras().get("data");
                mPhotoConteiner2.setImageBitmap(photo);
            }

            break;
        case 1:
            if(resultCode == RESULT_OK){
                Uri selectedImage = imageReturnedIntent.getData();
                mPhotoConteiner2.setImageURI(selectedImage);
            }
            break;
        case 2:
            if(resultCode == RESULT_OK){
                Bitmap photo = (Bitmap) imageReturnedIntent.getExtras().get("data");
                mPhotoConteiner1.setImageBitmap(photo);
            }

            break;
        case 3:
            if(resultCode == RESULT_OK){
                Uri selectedImage = imageReturnedIntent.getData();
                mPhotoConteiner1.setImageURI(selectedImage);
            }
            break;
    }
}

它崩溃了

Bitmap photo = (Bitmap) imageReturnedIntent.getExtras().get("data");

案例2

对不起那个问题,我是android编程的新手。 并寻求帮助。

1 个答案:

答案 0 :(得分:0)

哦,问题在于,当我在错误的地方编写案例2和案例3的代码时。我应该在case3中编写case2代码,在case2中编写case3。