Question

我有两个班：vehicle.Tire和vehicle.Car。

package vehicle;
@Named
public class Tire {
    private String age;
}

package vehicle;
@Named
public class Car {
    private Tire tire;

    // Spring calls this setter because default-autowire="byName" of xml configuration
    public void setTire(Tire newTire) {
        this.tire = newTire;
    }

    public Tire getTire() {
        return this.tire;
    }
}

以下spring xml工作正常。

<beans xmlns="http://www.springframework.org/schema/beans" 
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xmlns:context="http://www.springframework.org/schema/context"
   xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.1.xsd
                       http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.1.xsd
   default-autowire="byName">

  <context:component-scan base-package="vehicle" />

</beans>

我尝试在上面创建一个java配置：

@Configuration
@ComponentScan(basePackages={"vehicle"})
public VehicleConfig {
}

我不在类中使用@Inject或@Autowired注释，但是spring autowires 并且它适用于xml。使用java配置，不会调用Car的方法setTire :(

缺少什么？如何更改java配置使用组件扫描而不修改Car and Tire类？是否 default-autowire =“byName” xml标记属性在java中等效？

我使用上面的类来测试java配置

@Test
public class VehicleConfigTest  {    
    public void testTire() {
        AnnotationConfigApplicationContext applicationContext = 
            new AnnotationConfigApplicationContext();

        applicationContext.register(VehicleConfig.class);

        applicationContext.refresh();

        Car car = applicationContext.getBean(Car.class);
        Assert.assertNotNull(car.getTire());
    }

}

提前致谢。

使用隐式setter自动装配和ComponentScan将spring xml转换为java配置

0 个答案: