Question

这是代码......

extern GetStdHandle
extern GetModuleFileNameW
extern WriteFile
extern ExitProcess

import GetStdHandle kernel32.dll
import GetModuleFileNameW kernel32.dll
import WriteFile kernel32.dll
import ExitProcess kernel32.dll

global ..start

segment .code USE32

..start:

push dword -11
call [GetStdHandle]
mov dword [hStdOut], eax

;Getting the filepath of exe on disk...
push dword 256 ;MAX_PATH
push dword [filepath] ;Pointer to the buffer
push dword 0 ;NULL
call [GetModuleFileNameW]

;Trying to output the filepath...
push dword 0
push dword nBytes
push dword 256 ;MAX_PATH
push dword filepath
push dword [hStdOut]
call [WriteFile]

xor eax, eax
push eax
call [ExitProcess]

segment .data

segment .bss
hStdOut resd 1
nBytes resd 1
filepath resd 32

我已经玩了一下，我得到的只是一个空白输出。当我稍微玩一下时，我也得到了一堆胡言乱语。仍然没有文件路径，仍然没有快乐。我有预感，我对GetModuleFileNameW做错了什么，但我无法确定。我按照微软网站上的文档进行操作，并按照你在汇编语言中应该采用的相反顺序放置参数。我做错了什么？

Answer 1

;Getting the filepath of exe on disk...
push dword 256 ;MAX_PATH
push dword [filepath] ;Pointer to the buffer
push dword 0 ;NULL
call [GetModuleFileNameW]

...必须改为......

;Getting the filepath of exe on disk...
push dword 256 ;MAX_PATH
push dword filepath ;Pointer to the buffer
push dword 0 ;NULL
call [GetModuleFileNameW]

NASM x86程序集中的GetModuleFileName

1 个答案: