Question

我想在Umbraco中触发 BeginRequest 事件，但它不起作用。其余的代码工作正常。

public class ApplicationEventHandler : IApplicationEventHandler
{
    public void OnApplicationStarting(UmbracoApplicationBase umbracoApplication, ApplicationContext applicationContext) { }

    public void OnApplicationInitialized(UmbracoApplicationBase umbracoApplication, ApplicationContext applicationContext) { }

    public void OnApplicationStarted(UmbracoApplicationBase umbracoApplication, ApplicationContext applicationContext)
    {
        umbracoApplication.BeginRequest += umbracoApplication_BeginRequest;

        BundleConfig.RegisterBundles(BundleTable.Bundles);
        FilterConfig.RegisterGlobalFilters(GlobalFilters.Filters);
    }

    void umbracoApplication_BeginRequest(object sender, EventArgs e)
    {
        // Create HttpApplication and HttpContext objects to access
        // request and response properties.
        UmbracoApplicationBase application = (UmbracoApplicationBase)sender;
        HttpContext context = application.Context;

        if (context.Response.Cookies[Const.LANGUAGE_COOKIE_NAME] == null)
        {
            context.Response.Cookies.Add(new HttpCookie(Const.LANGUAGE_COOKIE_NAME, Thread.CurrentThread.CurrentUICulture.Name));
            return;
        }

        //cookie exists already
        else
        {
            //if no 404 
            if (UmbracoContext.Current.PublishedContentRequest != null && !UmbracoContext.Current.PublishedContentRequest.Is404)
            {
                //cookie value different than the current thread: user switched language.
                if (context.Response.Cookies[Const.LANGUAGE_COOKIE_NAME].Value != Thread.CurrentThread.CurrentUICulture.Name)
                {
                    //we set the cookie
                    context.Response.Cookies[Const.LANGUAGE_COOKIE_NAME].Value = Thread.CurrentThread.CurrentUICulture.Name;
                }
            }
        }
    } 
}

你知道它为什么不起作用吗？我正在使用umbraco 7，本地IIS（不是快速），我无法在函数 umbracoApplication_BeginRequest 中记录消息。

Answer 1

这是我能够在Umbraco 7.1.2实例中附加到BeginRequest的方式。首先创建一个继承自UmbracoApplication的新类（参见下面的示例），然后更新global.asax以继承新类。

public class MyUmbracoApplication : Umbraco.Web.UmbracoApplication
{
    private void Application_BeginRequest(object sender, EventArgs e)
    {
        /*  Your code here */
    }
}

Answer 2

根据这个，你应该在v6.1.0和forward中实现ApplicationEventHandler而不是IApplicationEventHandler：https://our.umbraco.org/documentation/Reference/Events/application-startup

Answer 3

首先，您应该创建一个继承 System.Web.IHttpModule 接口的 HttpModel 类

public class HttpModule : IHttpModule
{
    void IHttpModule.Init(HttpApplication context)
    {
        context.BeginRequest += ContextBeginRequest;
    }

    private void ContextBeginRequest(object sender, EventArgs e)
    {
        HttpApplication app = sender as HttpApplication;

        if (app != null)
        {
            //do stuff
        }
    }

    void IHttpModule.Dispose()
    {
        // Nothing to dispose; 
    }
}

然后，在你的web.config

中

<system.webServer><modules runAllManagedModulesForAllRequests="true">
  <remove name="DoStuff" />
  <add name="DoStuff" type="YourNameSpace.HttpModule, YourAssembly" /></modules></system.webServer>

Umbraco应用程序BeginRequest永远不会被解雇

3 个答案: