SVG过滤器元素剪切引用路径

时间:2015-07-02 16:00:05

标签: javascript svg

我发现svg过滤器元素与路径元素一起使用时会出现问题。当路径元素有像这个d="M28,46L28,23L77,23"这样的指令来渲染两条正交线时,它可以正常工作,滤镜和阴影渲染按预期方式,但随着其中一条线的长度接近零,出现了一个问题:路径元素(包括任何标记)开始被过滤器剪切 我不明白究竟发生了什么,但似乎过滤器的边界框(路径边界框的百分比)会折叠到零高度,这会以某种方式剪切引用路径元素。一旦路径边界框变为零,问题就会消失(至少在Chrome和Opera中会消失...)。

我找不到任何关于此的错误报告,有人能解释这种行为和/或建议一种处理它的方法吗?

  var width = 300,
    height = 100,
    constant = 10;

  var svg = d3.select('body').append('svg')
    .attr('width', width)
    .attr('height', height);

  var defs = svg.append("defs");
  var markerW = 8,
    markerH = 6,
    marker = defs.append('marker')
    .attr('id', "triangle")
    .attr('viewBox', "0 0 10 10")
    .attr('refX', "0")
    .attr('refY', 5)
    .attr('markerUnits', 'strokeWidth')
    .attr('markerWidth', markerW)
    .attr('markerHeight', markerH)
    .attr('orient', 'auto')

  var path = marker.append('path')
    .attr('d', "M 0 0 L 10 5 L 0 10 z")

  // create filter with id #drop-shadow
  // height=130% so that the shadow is not clipped
  var filter = defs.append("filter")
    .attr("id", "drop-shadow")
    .attr({
      "height": "200%",
      "width": "200%",
      x: "-50%",
      y: "-50%"
    })
    /*.style({opacity: 0.5})*/
  ;

  // SourceAlpha refers to opacity of graphic that this filter will be applied to
  // convolve that with a Gaussian with standard deviation 3 and store result
  // in blur
  filter.append("feGaussianBlur")
    .attr("in", "SourceAlpha")
    .attr("stdDeviation", 1)
    .attr("result", "blur");

  // translate output of Gaussian blur to the right and downwards with 2px
  // store result in offsetBlur
  var feOffset = filter.append("feOffset")
    .attr("in", "blur")
    .attr("dx", 2)
    .attr("dy", 2)
    .attr("result", "offsetBlur");

  // overlay original SourceGraphic over translated blurred opacity by using
  // feMerge filter. Order of specifying inputs is important!
  var feMerge = filter.append("feMerge");

  feMerge.append("feMergeNode")
    .attr("in", "offsetBlur")
  feMerge.append("feMergeNode")
    .attr("in", "SourceGraphic");

  var connector = d3.svg.line().interpolate("linear")
    .x(function(d) {
      return Math.round(d[0])
    })
    .y(function(d) {
      return Math.round(d[1])
    });

  function linkPath(d) {
    var x1 = d[0][0],
      y1 = d[0][1],
      x2 = d[1][0],
      y2 = d[1][1];
    return connector([
      [x1, y1],
      [x1, y2],
      [x2, y2]
    ]);
  }
  var link = svg.selectAll('.link')
    .data([
      [
        [10, 40],
        [200, 40]
      ]
    ])
    .enter()
    .append('path').attr("class", "link")
    .attr("stroke-width", "2")
    .attr('marker-end', 'url(#triangle)')
    .attr('stroke', 'black')
    .attr("fill", "none")
    .style("filter", "url(#drop-shadow)")
    .attr("d", linkPath)

  function start() {
    var t = 3000;
    link.data([
        [
          [10, 60],
          [200, 40]
        ]
      ])
      .transition().delay(t / 3).duration(t).ease("linear")
      .attr("d", linkPath)
      .each("end", function() {
        link.data([
            [
              [10, 40],
              [200, 40]
            ]
          ])
          .transition().duration(t).ease("linear")
          .attr("d", linkPath)
          .each("end", function() {
            link.data([
                [
                  [10, 20],
                  [200, 40]
                ]
              ])
              .transition().delay(t / 3).duration(t).ease("linear")
              .attr("d", linkPath)
              .each("end", function() {
                link.data([
                    [
                      [10, 40],
                      [200, 40]
                    ]
                  ])
                  .transition().duration(t).ease("linear")
                  .attr("d", linkPath)
                  .each("end", start)
              })
          })
      })
  };
  start();
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>

2 个答案:

答案 0 :(得分:1)

在调整过滤器区域大小时,不同浏览器的行为会有所不同。它们中的一些忽略了笔划宽度 - 因此当您获得水平或垂直线时,过滤器区域会折叠为零。您可以通过在userSpace单元中指定过滤器区域,或者将过滤器放在具有显式尺寸的包装g元素上来修复它。

答案 1 :(得分:1)

The Filter Effects Region中的特定文本,该文本使用x,{{1 }},ywidth属性描述了过滤器适用的区域。

如果按百分比定义它,它会随着路径边界框的缩小而缩小。即使您使用较大的百分比,它也会在边界框中折叠为零。这就是你剪裁的原因。

好消息是你不必使用百分比。只需在适当的坐标中指定过滤区域即可。

height
  var width = 300,
    height = 100,
    constant = 10;

  var svg = d3.select('body').append('svg')
    .attr('width', width)
    .attr('height', height);

  var defs = svg.append("defs");
  var markerW = 8,
    markerH = 6,
    marker = defs.append('marker')
    .attr('id', "triangle")
    .attr('viewBox', "0 0 10 10")
    .attr('refX', "0")
    .attr('refY', 5)
    .attr('markerUnits', 'strokeWidth')
    .attr('markerWidth', markerW)
    .attr('markerHeight', markerH)
    .attr('orient', 'auto')

  var path = marker.append('path')
    .attr('d', "M 0 0 L 10 5 L 0 10 z")

  // create filter with id #drop-shadow
  // height=100 pixels so that the shadow is not clipped
  var filter = defs.append("filter")
    .attr("id", "drop-shadow")
    .attr("filterUnits", "userSpaceOnUse")
    .attr({
      "height": "100",
      "width": "300",
      x: "-50",
      y: "-50"
    })
    /*.style({opacity: 0.5})*/
  ;

  // SourceAlpha refers to opacity of graphic that this filter will be applied to
  // convolve that with a Gaussian with standard deviation 3 and store result
  // in blur
  filter.append("feGaussianBlur")
    .attr("in", "SourceAlpha")
    .attr("stdDeviation", 1)
    .attr("result", "blur");

  // translate output of Gaussian blur to the right and downwards with 2px
  // store result in offsetBlur
  var feOffset = filter.append("feOffset")
    .attr("in", "blur")
    .attr("dx", 2)
    .attr("dy", 2)
    .attr("result", "offsetBlur");

  // overlay original SourceGraphic over translated blurred opacity by using
  // feMerge filter. Order of specifying inputs is important!
  var feMerge = filter.append("feMerge");

  feMerge.append("feMergeNode")
    .attr("in", "offsetBlur")
  feMerge.append("feMergeNode")
    .attr("in", "SourceGraphic");

  var connector = d3.svg.line().interpolate("linear")
    .x(function(d) {
      return Math.round(d[0])
    })
    .y(function(d) {
      return Math.round(d[1])
    });

  function linkPath(d) {
    var x1 = d[0][0],
      y1 = d[0][1],
      x2 = d[1][0],
      y2 = d[1][1];
    return connector([
      [x1, y1],
      [x1, y2],
      [x2, y2]
    ]);
  }
  var link = svg.selectAll('.link')
    .data([
      [
        [10, 40],
        [200, 40]
      ]
    ])
    .enter()
    .append('path').attr("class", "link")
    .attr("stroke-width", "2")
    .attr('marker-end', 'url(#triangle)')
    .attr('stroke', 'black')
    .attr("fill", "none")
    .style("filter", "url(#drop-shadow)")
    .attr("d", linkPath)

  function start() {
    var t = 3000;
    link.data([
        [
          [10, 60],
          [200, 40]
        ]
      ])
      .transition().delay(t / 3).duration(t).ease("linear")
      .attr("d", linkPath)
      .each("end", function() {
        link.data([
            [
              [10, 40],
              [200, 40]
            ]
          ])
          .transition().duration(t).ease("linear")
          .attr("d", linkPath)
          .each("end", function() {
            link.data([
                [
                  [10, 20],
                  [200, 40]
                ]
              ])
              .transition().delay(t / 3).duration(t).ease("linear")
              .attr("d", linkPath)
              .each("end", function() {
                link.data([
                    [
                      [10, 40],
                      [200, 40]
                    ]
                  ])
                  .transition().duration(t).ease("linear")
                  .attr("d", linkPath)
                  .each("end", start)
              })
          })
      })
  };
  start();