我有以下查询:
select r.people_code_id [People Code ID], r.resident_commuter [Campus6],
c1.udormcom [AG], aR.RESIDENT_COMMUTER [AG Bridge], ar.ACADEMIC_SESSION,
ar.ACADEMIC_TERM, ar.academic_year, ar.revision_date
from RESIDENCY r
left join AG_Common..CONTACT1 c1 on r.PEOPLE_CODE_ID=c1.key4
left join AG_Common..CONTACT2 c2 on c1.ACCOUNTNO=c2.accountno
left join AGPCBridge..ArchiveRESIDENCY aR on r.PEOPLE_CODE_ID=aR.PEOPLE_CODE_ID
where r.ACADEMIC_YEAR='2010'
and r.ACADEMIC_TERM='Fall'
and SUBSTRING(c1.udormcom,1,1)<>r.resident_commuter
and r.ACADEMIC_SESSION='Und 01'
and aR.ACADEMIC_SESSION='Und 01'
and aR.ACADEMIC_TERM='Fall'
and aR.ACADEMIC_YEAR='2010'
and SUBSTRING(c1.udormcom,1,1)=aR.RESIDENT_COMMUTER
我需要在where段中添加另一个子句。我有这个问题:
select DISTINCT * from RESIDENCY where ACADEMIC_YEAR='2010' and
ACADEMIC_TERM='Fall' and ACADEMIC_SESSION='Und 01' ORDER BY revision_date DESC
这只获得每个人的最新行。我想做(伪代码):
WHERE r.people_code_id and r.revision_date are in (select DISTINCT * from
RESIDENCY where ACADEMIC_YEAR='2010' and ACADEMIC_TERM='Fall' and
ACADEMIC_SESSION='Und 01' ORDER BY revision_date DESC)
我在SQL 2000兼容模式下运行(尽管它实际上运行的是SQL 2008)。
答案 0 :(得分:2)
我根据您要添加的内容重新编写了您的查询:
WITH residency_cte AS (
SELECT TOP (1)
r.people_code_id,
r.resident_commuter,
r.academic_year,
r.academic_term,
r.academic_session
FROM RESIDENCY r
WHERE r.academic_year = '2010'
AND r.academic_term = 'Fall'
AND r.academic_session = 'Und 01'
ORDER BY revision_date DESC)
SELECT r.people_code_id,
r.resident_commuter [Campus6],
c1.udormcom [AG],
aR.RESIDENT_COMMUTER,
ar.ACADEMIC_SESSION,
ar.ACADEMIC_TERM,
ar.academic_year,
ar.revision_date
FROM residency_cte r
LEFT JOIN AG_Common..CONTACT1 c1 ON c1.key4 = r.PEOPLE_CODE_ID
AND SUBSTRING(c1.udormcom, 1, 1) != r.resident_commuter
LEFT JOIN AG_Common..CONTACT2 c2 ON c2.accountno = c1.ACCOUNTNO
LEFT JOIN AGPCBridge..ArchiveRESIDENCY aR ON aR.PEOPLE_CODE_ID = r.PEOPLE_CODE_ID
AND aR.ACADEMIC_SESSION = r.academic_session
AND aR.ACADEMIC_TERM = r.academic_term
AND aR.ACADEMIC_YEAR = r.academic_year
AND SUBSTRING(c1.udormcom, 1, 1) = aR.RESIDENT_COMMUTER
唯一的事情是udormcom
列位置 - 一旦我知道它来自哪个表,我就会将该子句移动到连接中。我还将联接更新到ArchiveRESIDENCY
表,因此您只需要在一个地方调整日期。
但请注意,使用子字符串匹配另一列将永远不会很好 - 直到数据模型更改为正确,这将永远不会真正优化。
答案 1 :(得分:1)
您可以使用带有子查询的EXISTS
select
r.people_code_id [People Code ID],
r.resident_commuter [Campus6],
udormcom [AG],
aR.RESIDENT_COMMUTER [AG Bridge],
ar.ACADEMIC_SESSION,
ar.ACADEMIC_TERM,
ar.academic_year,
ar.revision_date
from RESIDENCY r
left join AG_Common..CONTACT1 c1
on r.PEOPLE_CODE_ID=c1.key4
left join AG_Common..CONTACT2 c2
on c1.ACCOUNTNO=c2.accountno
left join AGPCBridge..ArchiveRESIDENCY aR
on r.PEOPLE_CODE_ID=aR.PEOPLE_CODE_ID
where r.ACADEMIC_YEAR='2010'
and r.ACADEMIC_TERM='Fall'
and SUBSTRING(udormcom,1,1)<>r.resident_commuter
and r.ACADEMIC_SESSION='Und 01'
and aR.ACADEMIC_SESSION='Und 01'
and aR.ACADEMIC_TERM='Fall'
and aR.ACADEMIC_YEAR='2010'
and SUBSTRING(udormcom,1,1)=aR.RESIDENT_COMMUTER
and EXISTS
(
select 1
FROM RESIDENCY r2
where 1=1
and r2.revision_date = ar.revision_date /* note the join here */
and ACADEMIC_YEAR='2010'
and ACADEMIC_TERM='Fall'
and ACADEMIC_SESSION='Und 01'
/* the order by has been removed */
)
答案 2 :(得分:0)
WHERE r.people_code_id in (select DISTINCT people_code_id
from RESIDENCY
where ACADEMIC_YEAR='2010'
and ACADEMIC_TERM='Fall'
and ACADEMIC_SESSION='Und 01'
and revision_date = r.revision_date
ORDER BY revision_date DESC)
我认为你不需要'distinct'或'order by'。删除它们可以提高性能。