我在oracle上有三个用户并且他们有相同的表空间，当我运行以下查询时，我在执行查询时遇到以下问题。并且在执行它时需要花费很多时间:(
ORA-01652: unable to extend temp segment by 128 in tablespace TEMP
01652. 00000 - "unable to extend temp segment by %s in tablespace %s"
*Cause: Failed to allocate an extent of the required number of blocks for
a temporary segment in the tablespace indicated.
*Action: Use ALTER TABLESPACE ADD DATAFILE statement to add one or more
files to the tablespace indicated.
查询：
SELECT A.*
FROM LEA_AGREEMENT_DTL_RCL A,
nbfc_customer_m b,
db1.NBFC_PRODUCT_M c,
db1.LEA_INSTRUMENT_DTL e,
db1.LEA_LOANTYPE_M f,
db1.NBFC_BRANCH_M g,
ETRUPTI_CUST_AGRMNT_MAPPING h,
(SELECT A.caseid,
SUM (
CASE
WHEN b.chargecodeid = 82
AND A.ADVICETYPE = 'R'
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END) AS preemioverdue,
SUM (
CASE
WHEN b.chargecodeid = 9
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END) AS installmentoverdue,
SUM (
CASE
WHEN b.chargecodeid = 37
AND A.ADVICETYPE = 'P'
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END) AS unadjustedamount,
SUM (
CASE
WHEN b.chargecodeid = 8
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END) AS chequebounce,
SUM (
CASE
WHEN b.chargecodeid = 7
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END) AS LPP,
SUM (
CASE
WHEN b.chargecodeid NOT IN (82,9)
AND A.ADVICETYPE = 'R'
AND A.BPTYPE = 'LS'
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END ) AS otheroverdue,
SUM (
CASE
WHEN A.ADVICETYPE = 'R'
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END ) AS netreceivable,
MAX (c.balancetenure) AS balancetenure
FROM db1.NBFC_TXN_ADVICE_DTL A,
db1.NBFC_CHARGES_M b,
ETRUPTI_CUST_AGRMNT_MAPPING d,
(SELECT x.AGREEMENTID,
COUNT (1) AS balancetenure,
TO_CHAR (SUM(NVL(PRINCOMP,0)),'999,999,999,999,999,900.00')
FROM db1.LEA_REPAYSCH_DTL x,
ETRUPTI_CUST_AGRMNT_MAPPING y
WHERE x.billflage = 'N'
AND X.ADVFLAG ='N'
AND x.agreementid = y.agreementid
AND y.user_id = :user_id
GROUP BY x.AGREEMENTID
) c
WHERE A.status = 'A'
AND A.chargeid = b.chargeid
AND A.CASEID =C.AGREEMENTID
AND c.agreementid = d.agreementid
AND d.user_id = :user_id
AND A.PTXNADVICEID IS NULL
GROUP BY A.caseid
) BALANCES,
(SELECT w.agreementid,
COUNT(1) AS baltenure,
TO_CHAR (SUM(NVL(w.PRINCOMP,0)),'999,999,999,999,999,900.00') AS principalcomp
FROM db1.LEA_REPAYSCH_DTL w,
ETRUPTI_CUST_AGRMNT_MAPPING z
WHERE w.BILLFLAGE = 'N'
AND w.agreementid = z.agreementid
AND z.user_id = :user_id
GROUP BY w.agreementid
) repay
WHERE A.lesseeid = b.customerid
AND BALANCES.caseid(+)=A.proposalid
AND A.productflag = c.code(+)
AND A.proposalid = e.agreementid
AND c.loantype = f.loantype(+)
AND A.agreementid = repay.agreementid(+)
AND A.agreementid = h.agreementid
AND g.branchid(+) = a.service_branch
AND h.USER_ID = :user_id
如果可以以某种方式优化此查询，那么建议最受欢迎。
答案 0 :(得分：1)
尝试使用CTE。除此之外，您应该使用SQL ANSI-Syntax，通常它更容易阅读。
您与表格db1.nbfc_parameter_m进行交叉联接。这是故意吗？
with c as
(SELECT x.AGREEMENTID,
COUNT (1) AS balancetenure,
TO_CHAR (SUM(NVL(PRINCOMP,0)),'999,999,999,999,999,900.00')
FROM db1.LEA_REPAYSCH_DTL x
JOIN ETRUPTI_CUST_AGRMNT_MAPPING y ON x.agreementid = y.agreementid
WHERE x.billflage = 'N'
AND X.ADVFLAG ='N'
AND y.user_id = :user_id
GROUP BY x.AGREEMENTID
),
BALANCES AS
(SELECT A.caseid,
SUM (
CASE
WHEN b.chargecodeid = 82
AND A.ADVICETYPE = 'R'
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END) AS preemioverdue,
SUM (
CASE
WHEN b.chargecodeid = 9
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END) AS installmentoverdue,
SUM (
CASE
WHEN b.chargecodeid = 37
AND A.ADVICETYPE = 'P'
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END) AS unadjustedamount,
SUM (
CASE
WHEN b.chargecodeid = 8
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END) AS chequebounce,
SUM (
CASE
WHEN b.chargecodeid = 7
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END) AS LPP,
SUM (
CASE
WHEN b.chargecodeid NOT IN (82,9)
AND A.ADVICETYPE = 'R'
AND A.BPTYPE = 'LS'
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END ) AS otheroverdue,
SUM (
CASE
WHEN A.ADVICETYPE = 'R'
THEN NVL (A.adviceamt, 0) - NVL (A.txnadjustedamt, 0) - NVL (A.amtinprocess, 0)
ELSE 0
END ) AS netreceivable,
MAX (c.balancetenure) AS balancetenure
FROM db1.NBFC_TXN_ADVICE_DTL A
JOIN db1.NBFC_CHARGES_M b ON A.chargeid = b.chargeid
JOIN c ON A.CASEID = C.AGREEMENTID
JOIN ETRUPTI_CUST_AGRMNT_MAPPING d ON c.agreementid = d.agreementid
WHERE A.status = 'A'
AND d.user_id = :user_id
AND A.PTXNADVICEID IS NULL
GROUP BY A.caseid
),
repay AS
(SELECT w.agreementid,
COUNT(1) AS baltenure,
TO_CHAR (SUM(NVL(w.PRINCOMP,0)),'999,999,999,999,999,900.00') AS principalcomp
FROM db1.LEA_REPAYSCH_DTL w
JOIN ETRUPTI_CUST_AGRMNT_MAPPING z ON w.agreementid = z.agreementid
WHERE w.BILLFLAGE = 'N'
AND z.user_id = :user_id
GROUP BY w.agreementid
)
SELECT A.*
FROM LEA_AGREEMENT_DTL_RCL A
JOIN nbfc_customer_m b ON A.lesseeid = b.customerid
RIGHT OUTER JOIN db1.NBFC_PRODUCT_M c ON A.productflag = c.code
CROSS JOIN db1.nbfc_parameter_m d -> There is no join condition! Is this by purpose a CROSS JOIN?
JOIN db1.LEA_INSTRUMENT_DTL e ON A.proposalid = e.agreementid
RIGHT OUTER JOIN db1.LEA_LOANTYPE_M f ON c.loantype = f.loantype
LEFT OUTER JOINdb1.NBFC_BRANCH_M g ON g.branchid = a.service_branch
JOIN ETRUPTI_CUST_AGRMNT_MAPPING h ON A.agreementid = h.agreementid
LEFT OUTER JOIN BALANCES ON BALANCES.caseid = A.proposalid
RIGHT OUTER JOIN repay ON A.agreementid = repay.agreementid
WHERE h.USER_ID = :user_id
也许我混合RIGHT OUTER JOIN和LEFT OUTER JOIN，我不再使用旧的Oracle连接语法了。