Question

我试图检索存储在hs_audit.sqlite的表T3中的最新版本的审计问题。我已经尝试了cur.exectute行的多个版本，但仍然得到一个结果=无。我是sqlite的新手，所以任何人都可以帮助我正确的语法。如果我按如下方式执行cur.execute行

cur.execute("SELECT hvq1 FROM T3 WHERE audit_ver = 1")

并删除

con.text_factory = str

它有效，所以我认为问题必须是在sqlite命令中使用变量。

max_audit_ver = 1
audit_questions = ["hvq1", "hvq2", "hvq3", "hvq4", "hvq5"]

        count = 0
        for quest in audit_questions:
            con = sqlite3.connect("hs_audit.sqlite")
            con.text_factory = str
            cur = con.cursor()
            cur.execute("SELECT '%s' FROM T3 WHERE audit_ver = '%s'" %  (quest, max_audit_version))
            result = cur.fetchone()
            con.close()
            print "Question =%s" % (quest)
            print "Audit Version =%s" % (max_audit_version)
            print "The Count Is =%s" % (count)
            print "The return from the DB is =%s" % (result)
            count += 1

Answer 1

记住synthax ...... max_audit_version和max_audit_ver

另一方面，你应该阅读this page，你会发现一些重要的注释，例如：

# Never do this -- insecure!
symbol = 'RHAT'
c.execute("SELECT * FROM stocks WHERE symbol = '%s'" % symbol)

# Do this instead
t = ('RHAT',)
c.execute('SELECT * FROM stocks WHERE symbol=?', t)
print c.fetchone()

# Larger example that inserts many records at a time
purchases = [('2006-03-28', 'BUY', 'IBM', 1000, 45.00),
             ('2006-04-05', 'BUY', 'MSFT', 1000, 72.00),
             ('2006-04-06', 'SELL', 'IBM', 500, 53.00),
            ]
c.executemany('INSERT INTO stocks VALUES (?,?,?,?,?)', purchases)

无法从mySqlite3中检索str

1 个答案: