如何使用photo_reference从谷歌json响应中显示图像？

Question

我从Google API获得JSON响应。但JSON中有一个名为photo_reference的标签。如何使用该标签显示图像。

Answer 1

Queue

Answer 2

经过大量的研究后，我得到了我正在寻找的答案。

思想，将来会对某人有所帮助。

步骤：

1. JSON解析链接，我得到了一个键/值对数据集 NSDictionary 名为 jsonResponse 。

NSDictionary * jsonResponse = [NSJSONSerialization JSONObjectWithData：数据选项：0错误：＆amp;错误];

1. 然后，我将密钥 结果 的值存储在另一个中 字典名为placesResultDictionary，它位于给定的代码中 下方。

NSDictionary * result = [jsonResponse valueForKey：@＆＃34; result＆＃34;];     NSArray * photos = [placesResultDictionary valueForKey：@＆＃34;照片＆＃34;];

            if([photos isKindOfClass:[NSArray class]])
            {
                for (NSDictionary *dictionary in photos)
                {
                    NSString *photoReference = [NSString stringWithFormat:@"%@",[dictionary valueForKey:@"photo_reference"]];
                    NSString *maxWidth = [NSString stringWithFormat:@"%@",[dictionary valueForKeyPath:@"width"]];

                    NSURL *photoURL = [NSURL URLWithString:[NSString stringWithFormat:@"https://maps.googleapis.com/maps/api/place/photo?maxwidth=%@&photoreference=%@&key=%s",maxWidth,photoReference,GOOGLE_API_KEY]];

                    NSData *photoData = [NSData dataWithContentsOfURL:photoURL];

                    UIImage *image = [UIImage imageWithData:photoData];

                    [place_photos addObject:image];
                }
            }
            else
            {
                UIImage *image = [UIImage imageNamed:@"cell_placeHolder.png"];

                [place_photos addObject:image];
            }

<强>夫特

    if (photos is [Any]) {
                for dictionary: [AnyHashable: Any] in photos {
                    let photoReference: String? = "\(dictionary.value(forKey: "photo_reference") as? String)"
                    let maxWidth: String = "\(dictionary.value(forKeyPath: "width"))"
                    let photoURL = URL(string: "https://maps.googleapis.com/maps/api/place/photo?maxwidth=\(maxWidth)&photoreference=\(photoReference)&key=\(GOOGLE_API_KEY)")
                    let photoData = Data(contentsOf: photoURL)
                    let image = UIImage(data: photoData)
                    place_photos.append(image)
                }
    }