Python继续在“while True”中询问raw_input

Question

如果答案不同于1或2，我需要python继续询问raw_input。

这里的例子是：

print """What do you want me to do?

1) Press 1 if you want to .....
2) Press 2 if you want to ....."""

while True:
    answer1 = raw_input(" => ")

    if (answer1 == 1):
        ....
        ....

    elif (answer1 == 2):
        ....
        ....

    elif (answer1 != 1 or 2) or answer1.isalpha():
        print "I need 1 or 2"

问题是如果用户输入1或2，python也会继续询问raw_input。 我哪里错了？

Answer 1

如果答案为break或if，则应在elif和1块中添加2语句，以打破while循环。< / p>

示例 -

if (answer1 == 1):
    ....
    ....
    break
elif (answer1 == 2):
    ....
    ....
    break