想要从文本文件中随机选择单词,而是从文本文件中打印所有内容

时间:2015-07-02 04:55:11

标签: java

我希望编译器randomly从文本中选择一个单词,而不是从文本文件中打印所有内容。现在,下面的代码是打印文本文件中的所有内容。我认为我的getWord方法存在问题,因为当我从main函数调用getWord方法时,我得到error

public class TextFile {

        protected static Scanner file;
        protected static List<String> words;


        public TextFile(){
            words = openFile();
        }

        private List<String> openFile() {

            //List<String> wordList = new ArrayList<String>();

                try {
                    file = new Scanner(new File("words.txt"));

                } catch (FileNotFoundException e) {
                    System.out.println("File Not Found");
                } catch (Exception e) {
                    System.out.println("IOEXCEPTION");
                }

                return words;
        }

        public void readFile() throws FileNotFoundException {

            //ArrayList<String> wordList = new ArrayList<String>();

            while(file.hasNext()){
                String a = file.nextLine();
                //Collections.shuffle(words);
                //String pickWord = words.get(1);
                //String[] a = 
                System.out.println(a);
            }
        }

        public void closeFile() {
            file.close();
        }

        public String getWord() {

            Random r = new Random(words.size());
            String randomWord = words.get(r.nextInt());
            //System.out.println(randomWord);

            return randomWord;
        }

        public static void main(String[] args) throws FileNotFoundException {

            try {

                TextFile file = new TextFile();

                file.openFile();
                file.readFile();

                file.closeFile();

            } catch (Exception e) {
                System.out.println("IOEXCEPTION");
            }
        }
    }

3 个答案:

答案 0 :(得分:0)

在openfile方法中你重新调整了一个&#34; word&#34;变量是 null为变量赋值

错误来自{getword();},因为您正在访问 null变量的属性是一个错误

     public List<String> readFile() throws FileNotFoundException {
       while(file.hasNext()){
            String a = file.nextLine();
            words.add(a);
            System.out.println(a);
        }
       return words;
    }

在return语句行调用&#34;中打开文件方法;返回readfile();&#34;并尝试你的代码\

无需在main方法中调用readfile方法

答案 1 :(得分:0)

您在调用getWord方法时遇到异常,因为它会在行IndexOutOfBoundsException处抛出String randomWord = words.get(r.nextInt());

getWord方法的PFB修正:

public String getWord() {
    //You can use any approach..Random or Collections
    //Random r = new Random();      
    //String randomWord = words.get(r.nextInt(words.size()));

    Collections.shuffle(words);
    String randomWord = words.get(1);

    return randomWord;
}

您应该再次正确填充words字段:

public void readFile() throws FileNotFoundException {

    words = new ArrayList<String>();

    while (file.hasNext())
        words.add(file.nextLine());
}

答案 2 :(得分:0)

试试这个。您不需要在main中使用getWord()方法。 另外,为类创建一个构造函数:

public TextFile() {
}

你的openFile()方法不需要返回字符串。

    private void openFile() {


          try {
                file = new Scanner(new File("words.txt"));

            } catch (FileNotFoundException e) {
                System.out.println("File Not Found");
            } catch (Exception e) {
                System.out.println("IOEXCEPTION");
            }
}

这是你的readFile()方法:   1)读取文件   2)将一行单词分成每个单词并将其放入数组中   3)然后,随机单词

public void readFile() throws FileNotFoundException {

    //  List<String> wordList = new ArrayList<String>();


        while(file.hasNext()){


            String line = file.nextLine(); //read file one line at a time

            String[] parseWords = line.split(" "); //Parse what you read


            int index = new Random().nextInt(parseWords.length);

            String randW = parseWords[index];
            System.out.println(randW);

        }
    }

在您的主要方法中:

TextFile file1 = new TextFile ();

file1.openFile();
file1.readFile();
file1.closeFile();