Question

我正在尝试使用包含子查询的BigQuery查询结果，返回一行而不是两行。我正在查询日志文件，所以我需要的所有数据都在同一个字段中。该领域数据的一个例子如下：

/?cv=p15.0.9350&ctyp=sp&bits=64&os_bits=64&hl=fr&hl=fr&os=win&osv=6.2

我一直在进行的查询如下：

SELECT day, Win, Mac 
  FROM
    (SELECT DATE(metadata.timestamp) AS day, COUNT(DISTINCT protoPayload.resource) AS Win
     FROM [su_dashboard_streamed_logs.appengine_googleapis_com_request_log_20150424]
     WHERE protoPayload.resource CONTAINS 'ctyp=sp'
     GROUP BY day),
    (SELECT DATE(metadata.timestamp) AS day, COUNT(DISTINCT protoPayload.resource) AS Mac
     FROM [request_log_20150424]
     WHERE protoPayload.resource CONTAINS 'ctyp=sm'
     GROUP BY day)
ORDER BY day

目前上面的查询返回：

Row day Win Mac  
1   2015-04-24  160516  null     
2   2015-04-24  null    109547

我希望结果如下：

Row day Win Mac
1 2015-04-24 160516 109547

有办法做到这一点吗？如果是这样，我们将非常感谢任何帮助。

谢谢

Answer 1

您希望JOIN两个子选择而不是联合它们。在BigQuery中，a comma within a FROM clause indicates a union：

注意：与许多其他基于SQL的系统不同，BigQuery使用逗号语法来指示表联合，而不是联接。

如果您在日期字段中JOIN，那么您可以将这两行压缩成一行，如下所示：

SELECT table_1.day as day, table_1.Win as Win, table_2.Mac AS Mac
  FROM
    (SELECT DATE(metadata.timestamp) AS day, COUNT(DISTINCT protoPayload.resource) AS Win
     FROM [su_dashboard_streamed_logs.appengine_googleapis_com_request_log_20150424]
     WHERE protoPayload.resource CONTAINS 'ctyp=sp'
     GROUP BY day) AS table_1
  JOIN
    (SELECT DATE(metadata.timestamp) AS day, COUNT(DISTINCT protoPayload.resource) AS Mac
     FROM [request_log_20150424]
     WHERE protoPayload.resource CONTAINS 'ctyp=sm'
     GROUP BY day) AS table_2
  ON table_1.day = table_2.day
ORDER BY day

BigQuery：按日期将子选择合并为一行

1 个答案: