Question

我的表格如下：

Name     Created
ganesh   2010-06-25 10:54:54 
vasant   2010-06-25 11:54:54 
charlie  2010-06-25 12:54:54 
sam      2010-06-25 13:54:54 
vasamtj  2010-06-25 01:54:54 
jack     2010-06-25 02:54:54 
nima     2010-06-24 10:54:54 
kumar    2010-06-24 10:54:54 
jay      2010-06-24 10:54:54 
paala    2010-06-23 10:54:54 
test1    2010-06-23 10:54:54 
jhon     2010-06-22 10:54:54

我想只显示今天的参赛作品，在这种情况下我不想增加时间：

SELECT  response FROM ost_ticket_response WHERE staff_id = 1 AND created ='now()'

此查询也会随时间检查。

Answer 1

您的表格信息不完整，但此查询可以满足您的需求：

SELECT *
FROM ost_ticket_response
WHERE DATE_FORMAT(Created, '%Y-%m-%d') = DATE_FORMAT(NOW(), '%Y-%m-%d');

您可以从代码

中传递字符串值DATE_FORMAT(NOW(), '%Y-%m-%d')，而不是'2010-06-25'

Answer 2

非常粗鲁，但是：

SELECT response FROM ost_ticket_response WHERE staff_id = 1 AND created BETWEEN from_days(to_days(now())) AND from_days(to_days(now())+1)

Answer 3

WHERE Created >= date_format(CURRENT_TIMESTAMP(),'%Y%m%d000000')

Answer 4

此查询解决了我的问题：

SELECT count( response_id ) as cnt, staff_id FROM ost_ticket_response WHERE CAST( created AS Date ) = CURRENT_DATE( ) GROUP BY staff_id

此查询是否有任何缺点？

Answer 5

为什么不：

SELECT response FROM ost_ticket_response WHERE staff_id = 1 AND DATE(created) = CURDATE()

MySQL日期查询

5 个答案: