我已经获得了这个JSON数据，我想将它解析为3个类别：“guid”，“exponent”和“modulus”。我该怎么办？感谢您的帮助！
2015-07-01 11：02：51.972 Acculunk KeyPad [4717：1667358]回复正文： { “ERROR_CODE”：0， “ERROR_MESSAGE”： “”， “指数”： “010001”， “GUID”： “855fd04f-0016-1805-a3be-84dbef17ffd6”， “弹性模量”： “C44274FBD65D79B7F9ADF5255A563A5B8B8438D30F8E2CAD16950BE8675827B94F4F8040D4A9563811F405F8E94A20A69DCC0CA590F8731803AB4682497C0DC2520AD2AEB2CC4ED159276335C83B4FB4CB44966448081C625DF88D019118B7448684743EFB6D6704F8F8BD79875ACAEFC541DA3661D0D00BDDF115382A64C5C5”， “tran_id”： “cb2e8149-4961-458a-a6b2-7443bdb01509”}
2015-07-01 11：03：37.175 Acculunk KeyPad [4717：1674710]终止，因为没有系统应用程序。
以下是代码：
NSString *temp2 = [NSString stringWithFormat:@"{\n \"partner_key\": \"%@\",\n \"auth_token\": \"QaU9QcFZ6xE7aiRRBge0wZ4p6E01GEbl\",\n \"payment_account_id\": \"%@\",\n \"card_number\": \"%@\",\n \"card_exp_date\": \"%@\",\n \"amount\": \"%@\",\n \"memo\": \"%@\",\n \"recipient\": {\n \"email\": \"%@\",\n \"mobile_phone\": \"%@\"\n }\n}",[Partner_Key text], [Payment_Account_ID text], [Card_Number text], [Card_Exp_Date text], [Amount text],[Memo text], [Recipient_Email text], [Recipient_Phone_Number text]];
NSLog(temp2);
NSURL *URL = [NSURL URLWithString:@"https://cert.payzur.com/payzurservices.svc/payment/send/initiate"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:URL];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:[temp2 dataUsingEncoding:NSUTF8StringEncoding]];
NSURLSession *session = [NSURLSession sharedSession];
NSURLSessionDataTask *task = [session dataTaskWithRequest:request
completionHandler:
^(NSData *data, NSURLResponse *response, NSError *error) {
if (error) {
// Handle error...
return;
}
if ([response isKindOfClass:[NSHTTPURLResponse class]]) {
NSLog(@"Response HTTP Status code: %ld\n", (long)[(NSHTTPURLResponse *)response statusCode]);
NSLog(@"Response HTTP Headers:\n%@\n", [(NSHTTPURLResponse *)response allHeaderFields]);
}
NSString* body = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(@"Response Body:\n%@\n", body);
NSData *jsonData = [body dataUsingEncoding:NSUTF8StringEncoding];
NSError *e;
NSDictionary *res = [NSJSONSerialization JSONObjectWithData:body options:nil error:&e];
if (res) {
NSNumber *errorCode = res[@"error_code"];
NSString *errorMessage = res[@"error_message"];
NSString *guid = res[@"guid"];
NSString *exponent = res[@"exponent"];
NSString *modulus = res[@"modulus"];
}
else {
NSLog(@"Error: %@", error);
}
}];
[task resume];
答案 0 :(得分：2)
假设此数据为NSData类型，您可以执行以下操作：
NSError *myError = nil;
NSDictionary *res = [NSJSONSerialization JSONObjectWithData:apiReturn options:0 error:&myError];
NSNumber *errorCode = res[@"error_code"];
NSString *errorMessage = res[@"error_message"];
NSString *guid = res[@"guid"];
NSString *exponent = res[@"exponent"]; // Maybe also a NSNumber?
NSString *modulus = res[@"modulus"];
数据将在五个变量中提供：
答案 1 :(得分：1)
使用+ JSONObjectWithData:options:error:创建NSDictionary JSON。
然后以通常的方式访问字典项目来访问元素。
ChristopherMäuer使用字面语法答案：
NSError *error;
NSDictionary *res = [NSJSONSerialization JSONObjectWithData:apiReturn options:0 error:&error];
if (res) {
NSNumber *errorCode = res[@"error_code"];
NSString *errorMessage = res[@"error_message"];
NSString *guid = res[@"guid"];
NSString *exponent = res[@"exponent"]; // Maybe also a NSNumber?
NSString *modulus = res[@"modulus"];
}
else {
NSLog(@"Error: %@", error);
}
更新了新的问题代码：
以下是示例代码，我已经重新构建了从注销中收到的数据：
NSString *responseBody = @"{\"error_code\":0,\"error_message\":\"\",\"exponent\":\"010001\",\"guid\":\"855fd04f-0016-1805-a3be-84dbef17ffd6\",\"modulus\":\"C44274FBD65D79B7F9ADF5255A563A5B8B8438D30F8E2CAD16950BE8675827B94F4F8040D4A9563811F405F8E94A20A69DCC0CA590F8731803AB4682497C0DC2520AD2AEB2CC4ED159276335C83B4FB4CB44966448081C625DF88D019118B7448684743EFB6D6704F8F8BD79875ACAEFC541DA3661D0D00BDDF115382A64C5C5\",\"tran_id\":\"cb2e8149-4961-458a-a6b2-7443bdb01509\"}";
NSData *data = [responseBody dataUsingEncoding:NSUTF8StringEncoding];
// The above was just to get `data` setup.
// The only function of the following two statements is to print the data as a string.
NSString* body = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(@"Response Body:\n%@\n", body);
//
// NSData *jsonData = [body dataUsingEncoding:NSUTF8StringEncoding];
NSError *error;
NSDictionary *res = [NSJSONSerialization JSONObjectWithData:data options:0 error:&error];
NSLog(@"res: \n%@", res);
if (res) {
NSNumber *errorCode = res[@"error_code"];
NSString *errorMessage = res[@"error_message"];
NSString *guid = res[@"guid"];
NSString *exponent = res[@"exponent"];
NSString *modulus = res[@"modulus"];
NSLog(@"errorCode: %@\nerrorMessage: %@\nguid: %@\nexponent: %@\nmodulus: %@", errorCode, errorMessage, guid, exponent, modulus);
}
else {
NSLog(@"Error: %@", error);
}
输出：
Response Body:
{"error_code":0,"error_message":"","exponent":"010001","guid":"855fd04f-0016-1805-a3be-84dbef17ffd6","modulus":"C44274FBD65D79B7F9ADF5255A563A5B8B8438D30F8E2CAD16950BE8675827B94F4F8040D4A9563811F405F8E94A20A69DCC0CA590F8731803AB4682497C0DC2520AD2AEB2CC4ED159276335C83B4FB4CB44966448081C625DF88D019118B7448684743EFB6D6704F8F8BD79875ACAEFC541DA3661D0D00BDDF115382A64C5C5","tran_id":"cb2e8149-4961-458a-a6b2-7443bdb01509"}
res:
{
"error_code" = 0;
"error_message" = "";
exponent = 010001;
guid = "855fd04f-0016-1805-a3be-84dbef17ffd6";
modulus = C44274FBD65D79B7F9ADF5255A563A5B8B8438D30F8E2CAD16950BE8675827B94F4F8040D4A9563811F405F8E94A20A69DCC0CA590F8731803AB4682497C0DC2520AD2AEB2CC4ED159276335C83B4FB4CB44966448081C625DF88D019118B7448684743EFB6D6704F8F8BD79875ACAEFC541DA3661D0D00BDDF115382A64C5C5;
"tran_id" = "cb2e8149-4961-458a-a6b2-7443bdb01509";
}
errorCode: 0
errorMessage:
guid: 855fd04f-0016-1805-a3be-84dbef17ffd6
exponent: 010001
modulus: C44274FBD65D79B7F9ADF5255A563A5B8B8438D30F8E2CAD16950BE8675827B94F4F8040D4A9563811F405F8E94A20A69DCC0CA590F8731803AB4682497C0DC2520AD2AEB2CC4ED159276335C83B4FB4CB44966448081C625DF88D019118B7448684743EFB6D6704F8F8BD79875ACAEFC541DA3661D0D00BDDF115382A64C5C5
答案 2 :(得分：0)
我建议你更换以下两行：
// Header
var p = p2.Range.Paragraphs.Add();
var x = p.Range.Paragraphs.Count;
p.Range.Text = String.Format(headerText + "\r\n");
p.Range.set_Style("Req Level " + layerNumber.ToString() + " - Body");
// Description
p2 = p.Range.Paragraphs.Add();
p2.Range.Text = String.Format(bodyText + "\r\n");
p2.Range.set_Style("Req Level " + layerNumber.ToString());
使用我提供的两个代码行：
NSString* body = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(@"Response Body:\n%@\n", body);
或以下内容：
NSError *error;
NSDictionary* responseData = [NSJSONSerialization JSONObjectWithData:data options:0 error:&error];
所以现在你有 NSDictionary *responseData = [[NSDictionary alloc] initWithDictionary:(NSDictionary *)data];
，NSDictionary，所以现在我们可以按如下方式解码你的JSON响应（我将整个代码如下）：
responseData因此，您在问题中粘贴的所有代码如下所示：
NSString* body = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSDictionary *responseData = [[NSDictionary alloc] initWithDictionary:(NSDictionary *)data];
NSString *guid = [responseData valueForKey:@"guid"];
NSString *exponent = [responseData valueForKey:@"exponent"];
NSString *modulus = [responseData valueForKey:@"modulus"];
NSLog(@"Decoded Response :\n guide : %@,\n exponent : %@,\n modulus : %@", guid, exponent, modulus);
答案 3 :(得分：-1)
好吧，你没有说明你如何获得数据，比如你已经在NSString中或者仍然在NSData中，所以我将假设你在NSData中拥有它。
NSData *json <- somehow I magically got jSON data into this
NSError *error = nil;
NSDictionary *jsonDict = [NSJSONSerialization JSONObjectWithData:json options:kNilOptions error:&error];
NSString guid = [NSString stringWithString:jsonDict[@"guid"];
NSString exponent = [NSString stringWithString:jsonDict[@"exponent"];
NSString modulus = [NSString stringWithString:jsonDict[@"modulus"];