Question

我有以下代码正常工作;

var text_max = 459;
    var text_used = 0;
    var sms_count = 0;
    $('#leftstring').html(text_max + '');
    $('#usedstring').html(text_used + '');
    $('#sms_count').html(sms_count + '');
    $(document).on("keyup","#Message", function() {
        var text_length = $('#Message').val().length;
        var text_remaining = text_max - text_length;
        var text_completed = text_used + text_length;
        if(text_length <= 152) {
            var smscounts =+ parseInt(smscounts)+1;
        }
        $('#leftstring').html(text_remaining + '');
        $('#usedstring').html(text_completed + '');
        $('#sms_count').html(smscounts + '');
    });

问题与sms_count正如我所尝试的那样：我有459个字符的限制，因此我想将其除以3，因此当字符达到{时{1}}，它应该计为152，然后对于下一个1，它应该计为152，然后对于最后2它应该计为152 < / p>

Answer 1

您可以使用Math.ceil()查找必须发送的最少邮件数。

var per_text = 152

$(document).on("keyup","#Message", function() {
    var text_length = $('#Message').val().length;
    var text_remaining = text_max - text_length;
    var text_completed = text_used + text_length;
    var smscounts = Math.ceil(text_length / per_text);

    $('#leftstring').html(text_remaining + '');
    $('#usedstring').html(text_completed + '');
    $('#sms_count').html(smscounts + '');
});

Answer 2

这应该从逻辑上完成你所说的：

    ...
    if(text_length <= 152) {
        var smscounts =+ parseInt(smscounts)+1;
    } else if (text_length <= 304) {
      //do logic
    } else { // it's > 304
      //do logic
    }
    ...

Answer 3

这有效：

var sms=152,text_max=3*sms; // good idea from caliburn, thanx ;-)
$(document).on("keyup","#Message", function() {
  var text_length = $('#Message').val().length;
  $('#leftstring').html((text_max - text_length) + '');
  $('#usedstring').html((text_length % sms) + '');
  $('#sms_count').html(Math.ceil(text_length / sms) + '');
});

见这里：http://jsfiddle.net/fkgpwhb5/

Answer 4

你想要这个

smscounts = Math.ceil(text_length / 152);

Math.ceil会向上舍入到最接近的整数。由于JavaScript划分有点不稳定，你可能不得不这样做

smscounts = Math.floor(text_length / 152) + 1;

在某个时刻到达时对字符进行计数

4 个答案: