Question

这是我的问题的小提琴http://jsfiddle.net/gxbwk6dk/7/

我有一个服务来查找json的元素，我从控制器那里调用了这个服务两次，但是我从两个调用得到的结果都是一样的。

示例

    string xml = @"<session xmlns=""http://test.net/schema/session/1.0"" name=""test"" start=""2015-07-01T07:20:31.425Z"">    
      <download>
        <filename value=""/UAT/Incoming/ Status/Archive/8-22-2011 3-20-14 PM306.xml"" />
        <result success=""false"">
          <message>Timeout waiting .</message>
        </result>
      </download>
    </session>";

    XmlDocument xdoc  = new XmlDocument();
    xdoc.LoadXml(xml);

    // Here, you load the namespace used in your xml. You'll need it later in your XPath queries
    XmlNamespaceManager nsmgr = new XmlNamespaceManager(xdoc.NameTable);
    nsmgr.AddNamespace("test", "http://test.net/schema/session/1.0");

    // XPath to select the "result" node whose attribute "success" equals false
    XmlElement xelt = xdoc.DocumentElement.SelectSingleNode("descendant::test:download/test:result[@success=\"false\"]", nsmgr) as XmlElement;

    // return the "message" node
    return xelt.FirstChild as XmlElement;

中的

和elementObj1具有相同的数据

欢迎任何解决方案。

＆＃13;

elementObj2

＆＃13;

var app=angular.module("myapp",[]);

app.controller("myctrl",function($scope,myservice)
{
console.log("add of two "+myservice.addTwo(5,7));

$scope.sum=myservice.addTwo(5,7);


$scope.sampleObj={
"glossary": {
"title": "example glossary",
"GlossDiv": {
"title": "S",
"GlossList": {
"GlossEntry": {
"ID": "SGML",
"SortAs": "SGML",
"GlossTerm": "Standard Generalized Markup Language",
"Acronym": "SGML",
"Abbrev": "ISO 8879:1986",
"GlossDef": {
"para": "A meta-markup language, used to create markup languages such as DocBook.",
"GlossSeeAlso": ["GML", "XML"]
},
"GlossSee": "markup"
}
}
}
}
};
   myservice.findElement($scope.sampleObj,'GlossEntry').then(function(data){
     $scope.elementObj1=data;
	 console.log("find element object1 ", $scope.elementObj1);
    });
    
    
    myservice.findElement($scope.sampleObj,'GlossList').then(function(data){
     $scope.elementObj2=data;
	 console.log("find element object2 ", $scope.elementObj2);
    });



}
);


app.factory("myservice",function($q,$timeout){
var deferred = $q.defer();
return{
	addTwo:addTwo,
	findElement:findEle,
	sample:sample
	
};

function sample(jsObject)
{
var deferred = $q.defer();
$timeout(function(){deferred.resolve(jsObject)},5000);
  
return deferred.promise;

}

	function addTwo(a,b)
	{
		return a+b;
	}

function findEle(jsObject,searchEle)
	{
         
	for(obj in jsObject)
	{
		console.log("obj "+obj+" mapobj "+jsObject[obj]);
		if(obj===searchEle)
		{
			console.log("element found "+obj);
             deferred.resolve(jsObject[obj]);
			
		}
		if(typeof jsObject[obj]==="object")
		findEle(jsObject[obj],searchEle);
			
	}
         return deferred.promise;
	}


});

＆＃13;

Answer 1

以下是一个有效的解决方案：http://jsfiddle.net/gxbwk6dk/9/

您正在返回相同的对象，我在您点击时进行了修改：

touchend

AngularJS：如何从角度分辨率获取数据？

1 个答案: