Question

for(int counter = 0; counter < args.length; counter++){
        System.out.println("Displaying per words: " + args[counter]);
        splitWords = args[counter].toCharArray();
        for(int counter2 = 0; counter2 < splitWords.length; counter2++){
            System.out.println("Word spliced: " + splitWords[counter2]);
            System.out.println("The number equivalent of " + splitWords[counter2] + " is "
                    + (int) splitWords[counter2]);
            occurenceCount[(int)splitWords[counter2]]++;
            System.out.println("The letter " + splitWords[counter2] + 
                    " was shown " + occurenceCount[(int)splitWords[counter2]] + " times.");


        }
    }

我的函数没有将counter2检测为变量，因为它位于嵌套的for循环中。那么我该如何摆脱这种困境呢？

我正在尝试使用参数输入（分别为字符串）并使用ascii表作为参考发布出现次数，正如您所看到的，阻止我完成此操作只有一个障碍。

有什么想法吗？

Answer 1

您的主要问题是您错过了一个重要事实 - 在您的循环完成之后，您的计数才会完成。

因此，您需要在第一个循环完成后在单独的循环中打印出您的计数。

public void test() {
    String[] args = {"Hello"};
    int[] occurenceCount = new int[256];
    for (int word = 0; word < args.length; word++) {
        System.out.println("Displaying per words: " + args[word]);
        char[] splitWords = args[word].toCharArray();
        for (int character = 0; character < splitWords.length; character++) {
            System.out.println("Word spliced: " + splitWords[character]);
            System.out.println("The number equivalent of " + splitWords[character] + " is "
                    + (int) splitWords[character]);
            occurenceCount[(int) splitWords[character]]++;
            System.out.println("Word spliced: " + splitWords[character]);
        }
    }
    // Scond loop to print the results.
    for (int character = 0; character < occurenceCount.length; character++) {
        int count = occurenceCount[character];
        if (count > 0) {
            System.out.println("The letter " + ((char) character)
                    + " was shown " + count + " times.");
        }

    }
}

尽管在嵌套的for循环中，我如何返回数组值？

1 个答案: