您好我有Java类，它将从文件读取和解析JSON数据并插入到DB中，它们存储NAME，AGE和PHONE。该程序运行正常;但我的要求是，我有一个不同的JSON数据需要执行相同的操作，我想存储 AGE ， ID 和 TYPE 。我在上一部分提到了我的JSON数据
我从https://javapages4all.wordpress.com/2012/12/10/read-from-json-file-and-persist-into-mysql/
获得了此代码test.json：
{'profiles':[
{'name':'Girish', 'age': 44, 'phone':'203-203-2030'},
{'name':'Alex','age':31, 'phone':'203-203-2030'},
{'name':'Amy', 'age': 24, 'phone':'203-203-2030'},
{'name':'Melissa','age':21, 'phone':'203-203-2030'}
]
}
Java类：
package com.sample.json;
import java.io.InputStream;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.SQLException;
import java.util.Iterator;
import net.sf.json.JSONArray;
import net.sf.json.JSONObject;
import net.sf.json.JSONSerializer;
import org.apache.commons.io.IOUtils;
public class MyJson {
private static String tableName = "jsontest";
public static void main(String[] args) {
try {
ClassLoader cl = MyJson.class.getClassLoader();
InputStream is = cl.getResourceAsStream("test.json");
String str = IOUtils.toString(is);
JSONObject jsonObject = (JSONObject) JSONSerializer.toJSON(str);
System.out.println(jsonObject);
JSONArray jsonArr = jsonObject.getJSONArray("profiles");
JSONObject obj = null;
JSONArray nameArr = null;
JSONArray valArr = null;
for (int i = 0; i < jsonArr.size(); i++) {
obj = jsonArr.getJSONObject(i);
nameArr = obj.names();
valArr = obj.toJSONArray(nameArr);
//saveRecord(nameArr, valArr);
}
} catch (Exception e) {
e.printStackTrace();
}
}
private static void saveRecord(JSONArray nameArray, JSONArray valArray) {
Connection conn = getConnection();
StringBuffer sb = new StringBuffer("insert into " + tableName + "(");
int size = nameArray.size();
int count = 0;
Iterator<Object> iterator = nameArray.iterator();
while (iterator.hasNext()) {
if (count < (size - 1))
sb.append(iterator.next() + ",");
else
sb.append(iterator.next() + ")");
count++;
}
sb.append(" values(");
for (int i = 0; i < size; i++) {
if (i < (size - 1))
sb.append("?,");
else
sb.append("?)");
}
System.out.println(sb.toString());
try {
PreparedStatement pstmt = conn.prepareStatement(sb.toString());
bindVariables(valArray, pstmt);
pstmt.executeUpdate();
} catch (SQLException e) {
e.printStackTrace();
}
}
private static void bindVariables(JSONArray valArray,
PreparedStatement pstmt) throws SQLException {
Iterator<Object> iterator = valArray.iterator();
int cnt = 0;
while (iterator.hasNext()) {
Object obj = iterator.next();
if (obj instanceof String) {
pstmt.setString(++cnt, (String) obj);
} else if (obj instanceof Integer) {
pstmt.setLong(++cnt, (Integer) obj);
} else if (obj instanceof Long) {
pstmt.setLong(++cnt, (Long) obj);
} else if (obj instanceof Double) {
pstmt.setDouble(++cnt, (Double) obj);
}
}
}
private static Connection getConnection() {
Connection con = null;
String url = "jdbc:mysql://localhost:3306/";
String db = "jsondata";
String driver = "com.mysql.jdbc.Driver";
String user = "root";
String pass = "root";
try {
Class.forName(driver);
con = DriverManager.getConnection(url + db, user, pass);
} catch (ClassNotFoundException e) {
e.printStackTrace();
} catch (SQLException e) {
e.printStackTrace();
}
return con;
}
}
我的JSON：
[{"emp":{"age":34,"ID":3423423},"type":"s"},
{"emp":{"age":43,"ID":324324235},"type":"s"},
{"emp":{"age":36,"ID":324324236},"type":"v"},
{"emp":{"age":46,"ID":324324238},"type":"s"},
{"emp":{"age":55,"ID":324324243},"type":"s"},
{"emp":{"age":44,"ID":324324287},"type":"s"}]
对于上面的程序我想使用这个JSON数据
答案 0 :(得分：2)
我使用Gson为您的案例做了一个简单示例，用于解析json。
public class Result {
private long id;
private int age;
private String type;
public Result(long id, int age, String type) {
this.age = age;
this.id = id;
this.type = type;
}
}
public class EmployeeInfo {
private int age;
@SerializedName("ID")
private long id;
public EmployeeInfo(int age, long id) {
this.age = age;
this.id = id;
}
}
public class Employee {
@SerializedName("emp")
private EmployeeInfo employeeInfo;
private String type;
public Employee(EmployeeInfo employeeInfo, String type) {
this.employeeInfo = employeeInfo;
this.type = type;
}
}
执行命令
public static void main(String[] args) throws IOException {
String json = "[{\"emp\":{\"age\":34,\"ID\":3423423},\"type\":\"s\"}, \n" +
"{\"emp\":{\"age\":43,\"ID\":324324235},\"type\":\"s\"}, \n" +
"{\"emp\":{\"age\":36,\"ID\":324324236},\"type\":\"v\"},\n" +
"{\"emp\":{\"age\":46,\"ID\":324324238},\"type\":\"s\"},\n" +
"{\"emp\":{\"age\":55,\"ID\":324324243},\"type\":\"s\"},\n" +
"{\"emp\":{\"age\":44,\"ID\":324324287},\"type\":\"s\"}]";
Gson gson = new Gson();
Type type = new TypeToken<List<Employee>>() {
}.getType();
List<Employee> employees = gson.fromJson(json, type);
List<Result> results = new ArrayList<>();
Result result;
for (Employee employee : employees) {
result = new Result(employee.getEmployeeInfo().getId(), employee.getEmployeeInfo().getAge(), employee.getType());
results.add(result);
}
System.out.println(gson.toJson(results));
}
答案 1 :(得分：1)
要做到这一点，您必须首先解析它并将其值保存在某处，然后创建具有所需格式的JSON对象，并通过第一阶段的解析值设置其值。 例如在Android / Java中：
ArrayList<YourDataNode> arrayList = new ArrayList<>();
for (int i=0 ; i<jsonArray.length() ; i++) {
JSONObject jsonObject = jsonArray.get(i);
JSONObject empObject = jsonObject.getJSONObject("emp");
String type = jsonObject.getString("type");
int age = empObject.getInt("age");
long id = empObject.getLong("id");
YourDataNode temp = new (id, age, type);
arrayList.add(temp);
}
答案 2 :(得分：1)
试试这个
import org.codehaus.jettison.json.JSONArray;
import org.codehaus.jettison.json.JSONException;
import org.codehaus.jettison.json.JSONObject;
public class GetDataFromJSON {
public static void main(String[] args) {
String json = "[{\"emp\":{\"age\":34,\"ID\":3423423},\"type\":\"s\"},"
+ "{\"emp\":{\"age\":43,\"ID\":324324235},\"type\":\"s\"},"
+ "{\"emp\":{\"age\":36,\"ID\":324324236},\"type\":\"v\"},"
+ "{\"emp\":{\"age\":46,\"ID\":324324238},\"type\":\"s\"},"
+ "{\"emp\":{\"age\":55,\"ID\":324324243},\"type\":\"s\"},"
+ "{\"emp\":{\"age\":44,\"ID\":324324287},\"type\":\"s\"}]";
JSONArray jsonArray = getDesiredJSONArray(json);
System.out.println(jsonArray);
}
public static JSONArray getDesiredJSONArray(String json) {
JSONArray jsonArray = null;
JSONArray desiredJsonArray = new JSONArray();
try {
jsonArray = new JSONArray(json);
for (int i = 0; i < jsonArray.length(); i++) {
// System.out.println(jsonArray.get(i));
JSONObject object = new JSONObject(jsonArray.get(i).toString());
JSONObject jsonObject = new JSONObject();
jsonObject.put("type", object.get("type"));
object = new JSONObject(object.get("emp").toString());
jsonObject.put("ID", object.get("ID"));
jsonObject.put("age", object.get("age"));
desiredJsonArray.put(jsonObject);
}
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return desiredJsonArray;
}
}