javascript代码中未终止的字符串文字,我也不确定PHP代码

时间:2015-07-01 06:16:20

标签: javascript php

enter image description here我在下面的代码中有一个错误,其中说UNTERMINATED STRING LITERAL请帮助我,并告诉我PHP代码是在正确的位置,因为它是在脚本标记之前,所以如何可以设置为真?

<!DOCTYPE html>
<html>
    <head>
    <meta charset="utf-8"/>
    </head>
    <body>
        <?php
            if(isset($_REQUEST['page']))
                {
                    $page=$_REQUEST['page'];
                }
        ?>
        <form action="yea.php" method="post">
            <select name="page" onchange="hitme('<?php echo $page;?>');">
                <option value="home">home</option>
                <option value="about">about</option>
                <option value="menu">menu</option>
                <option value="download">download</option>
            </select>
        </form>
        <script>
            function hitme(page)
                {
                    switch(page)
                        {
                            case "home":
                            document.write("you selected home");
                            break;

                            case "menu":
                            document.write("you selected menu");
                            break;

                            case "about":
                            document.write("you selected about");
                            break;

                            default:
                            document.write("invalid selection!");
                        }
                }

                document.write("<br>it will print no matter what!");
        </script>
    </body>
    </html>

3 个答案:

答案 0 :(得分:1)

我有问题,你在评论中提到为什么你需要php来做到这一点

        <form action="yea.php" method="post">
            <select name="page" onchange="hitme(this);">
                <option value="home">home</option>
                <option value="about">about</option>
                <option value="menu">menu</option>
                <option value="download">download</option>
            </select>

            <span id="pagename"></span>
        </form>
        <script>
            function hitme(page)
                {
                    switch(page.value)
                        {
                            case "home":
                            document.getElementById("pagename").innerHTML = "you selected home";
                            break;

                            case "menu":
                           document.getElementById("pagename").innerHTML = "you selected menu";
                            break;

                            case "about":
                             document.getElementById("pagename").innerHTML = "you selected about";

                            break;

                            default:
                             document.getElementById("pagename").innerHTML = "invalid selection!";

                        }
                }

                alert("<br>it will print no matter what!");
        </script>
    </body>

答案 1 :(得分:0)

将您的PHP代码更改为

<?php


            if(isset($_REQUEST['page']))
                {
                    $page=$_REQUEST['page'];
                }
                else
                $page="";
        ?>

答案 2 :(得分:0)

在PHP中,如果阻止你使用logal $ page,你需要使用全局。因此,您必须将$ page变量声明为if block。