Question

我正在创建具有UIDatePicker，UIPickerView和TableView的汽车的高级搜索，并且我遇到问题titleForRow。如果我隐藏一个选择器视图，我可以正确查看数据（得分）并看到另一个选秀视图（结果）。但是在我打开第二个选秀视图（结果）并打开另一个选秀视图（得分）而没有隐藏第一个选手时，当我尝试滚动得分选择器时我在titleForRow上有错误说＆＃34;数组索引超出范围＆＃34;。那么，如果我要在一个视图控制器上使用多个pickerview？我如何以正确的方式连接它们？请帮助吗？

这是我的2picker和1date选择器的设计，

Pic 1

正如您所看到的，当我点击一个静态表格单元格时，选择器出现，当我再次点击时，选择器隐藏。

这是我的高级搜索控制器

Pic 2

这是我用来控制我的pickerview和静态表格单元格的代码

var pickerCollection : String = "Score"

override func viewDidLoad() {
    TegKeychain.set("currentView", value: "Advance")
    super.viewDidLoad()
    datePickerChanged()
    //self.scorePicker?.delegate = self

    scoreDetailLabel.text = scoresValues[0]
    resultDetailLabel.text = resultsValues[0]

    detailLabel.text = venue
}

override func viewDidAppear(animated: Bool) {
    TegKeychain.set("currentView", value: "Advance")
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

override func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
    if indexPath.section == 0 && indexPath.row == 0 {
        toggleDatepicker()
    }
    if indexPath.section == 2 && indexPath.row == 0{
        pickerCollection = "Score"
        toggleScorePicker()
        scorePicker.reloadAllComponents()
    }
    if indexPath.section == 2 && indexPath.row == 2{
        pickerCollection = "Result"
        toggleResultPicker()
        resultPicker.reloadAllComponents()
    }
    println("Section : \(indexPath.section)")
    println("Row : \(indexPath.row)")
}

override func tableView(tableView: UITableView, heightForRowAtIndexPath indexPath: NSIndexPath) -> CGFloat {
    if datePickerHidden && indexPath.section == 0 && indexPath.row == 1 {
        return 0
    }
    else if scorePickerHidden && indexPath.section == 2 && indexPath.row == 1{
        return 0
    }
    else if resultPickerHidden && indexPath.section == 2 && indexPath.row == 3{
        return 0
    }
    return super.tableView(tableView, heightForRowAtIndexPath: indexPath)
}

func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
    return 1
}

func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
    if pickerCollection == "Score"{
        return scoresValues.count
    }
    if pickerCollection == "Result"{
        return resultsValues.count
    }
    return 0
}

func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String! {
    if pickerCollection == "Score"{
        return scoresValues[row]
    }
    if pickerCollection == "Result"{
        return resultsValues[row]
    }
    return ""
}

func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
    if pickerCollection == "Score"{
        scoreDetailLabel.text = scoresValues[row]
    }
    if pickerCollection == "Result"{
        resultDetailLabel.text = resultsValues[row]
    }
}

// I will not show Date Picker to make it simple.

结果选择器和分数选择器

/////////////////////////////////////////////////////// Scores ///////////////////////////////////////////////////////////////////

var scorePickerHidden = true

var scores :[String:String] = ["":"All","S":"S","R":"R","RA":"RA","above 5":"Above 5","above 4":"Above 4","above 3":"Above 3","above 2":"Above 2","above 1":"Above 1","above 0":"Above 0"]
var scoresValues : [String] = ["All","S","R","RA","Above 5","Above 4","Above 3","Above 2","Above 1","Above 0"]

func toggleScorePicker() {

    scorePickerHidden = !scorePickerHidden

    tableView.beginUpdates()
    tableView.endUpdates()

}

/////////////////////////////////////////////////////// Results ///////////////////////////////////////////////////////////////////

var resultPickerHidden = true

var results :[String:String] = ["":"All","not yet":"Not Yet","unsold":"Unsold","sold by nego":"Sold by nego","others":"Others"]
var resultsValues : [String] = ["All","Not Yet","Unsold","Sold by nego","Others"]

func toggleResultPicker() {

    resultPickerHidden = !resultPickerHidden

    tableView.beginUpdates()
    tableView.endUpdates()

}

请给我任何帮助和建议？我不能只使用单个选择器，因为它不符合我的设计。那么，有没有其他方法，我可以在适当的静态单元被轻敲时连接我正确的选择器视图？< / p>

Answer 1

如果要使用多个选择器视图，则必须在Attributes Inspector中使用tag属性。所以，假设我们有两个UIPickerView。在属性检查器中，将每个UIPickerView设置为标记＃1和另一个＃2。确保它们都连接到同一视图控制器的委托和数据源。

然后在你的代码中，

var scoresValues = []
var resultsValues = []

override func viewDidLoad(){
    super.viewDidLoad()
    scoreValues = ["a","b",...]
    resultsValue = ["c","d",...]   
}

func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
    return 1
}

func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
    if pickerView.tag == 1{
        return scoresValues.count
    }
    else{
        return resultsValues.count
    }
}

func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String! {
    if pickerView.tag == 1{
        return scoresValues[row]
    }
    else{
        return resultsValues[row]
    }
}

我所展示的仅使用2个选择器。如果你想使用更多的选择器，你可以使用if / else或switch来处理它们。

连接多个UIPickerView时，titleForRow出错

1 个答案: