我正在尝试为我的个人库创建一个可以处理所有内容的链接列表。我试着写它，以便它可以同样地＃＆＃39;轻松地int，null，DateTime或Class，我希望它可以轻松扩展，这样如果我想快速制作堆栈，我可以写push，pop和peek等方法。
目前，我的代码看起来像这样。请注意，我使用＆＃39; Base＆＃39;作为我的通用类型。
namespace ClassLibrary1
{
public class LinkedList<Base> where Base : class
{
public class Node
{
private Node next;
private Node prev;
private Base value;
/// <summary>
/// Constructor for Nodes of Circular Linked List class.
/// Calls overloaded constructor for no previous or next provided.
/// O(1)
/// </summary>
/// <param name="value">The value to be stored. Can use tuple for associations</param>
public Node(Base value)
{
new Node(null, null, value);
}
/// <summary>
/// Constructor for nodes of Circular Linked List class.
/// O(1)
/// </summary>
/// <param name="prev">The previous node in the linked list</param>
/// <param name="next">The next node in the linked list</param>
/// <param name="value">The value to be stored</param>
public Node(Node prev, Node next, Base value)
{
this.prev = prev;
this.next = next;
this.value = value;
}
/// <summary>
/// Sets the 'next' attribute of the node to the passed value.
/// O(1)
/// Chainable
/// </summary>
/// <param name="next">The new value of the 'next' attribute.</param>
/// <returns>Chainable(Node, this)</returns>
public Node setNext(Node next)
{
this.next = next;
return this;
}
/// <summary>
/// Sets the 'prev' attribute of the node to the passed value
/// O(1)
/// Chainable
/// </summary>
/// <param name="prev">The new value of the 'prev' attribute to denote the previous node</param>
/// <returns>Chainable(Node, this)</returns>
public Node setPrev(Node prev)
{
this.prev = prev;
return this;
}
/// <summary>
/// Changes the stored value of type Base to the passed value.
/// O(1)
/// Chainable
/// </summary>
/// <param name="value">The new value to be stored with the node</param>
/// <returns>Chainable(Node, this)</returns>
public Node setVal(Base value)
{
this.value = value;
return this;
}
/// <summary>
/// Returns the next node in the linked list.
/// O(1)
/// </summary>
/// <returns>The next node in the linked list.(Node)</returns>
public Node getNext()
{
return this.next;
}
/// <summary>
/// Returns the previous node in the linked list.
/// O(1)
/// </summary>
/// <returns>The previous node in the linked list.(Node)</returns>
public Node getPrev()
{
return this.prev;
}
/// <summary>
/// Returns the value stored at this node.
/// O(1)
/// </summary>
/// <returns>The value stored at this node.(Base)</returns>
public Base getVal()
{
return this.value;
}
}
public Node head;
public bool duplicates;
public bool hasNullValues;
public bool throwNullError;
/// <summary>
/// Constructor for the LinkedList. Creates a null head node.
/// Duplication defaulted to false
/// O(1)
/// </summary>
public LinkedList()
{
this.head = new Node(null);
this.head.setNext(this.head).setPrev(this.head);
this.duplicates = false;
this.hasNullValues = false;
this.throwNullError = false;
}
/// <summary>
/// Allows duplication for the linked list.
/// O(1)
/// Chainable attribute.
/// </summary>
/// <returns>Chainable.(LinkedList<Base>, this)</returns>
public LinkedList<Base> hasDuplicates()
{
this.duplicates = true;
return this;
}
/// <summary>
/// Allows the structure to store null values in nodes.
/// O(1)
/// Chainable.
/// </summary>
/// <returns>Chainable.(LinkedList<Base>, this)</returns>
public LinkedList<Base> hasNulls()
{
this.hasNullValues = true;
return this;
}
/// <summary>
/// Causes the structure to throw a null error when a null value is inserted.
/// If hasNulls is off, turns it on.
/// O(1)
/// Chainable.
/// </summary>
/// <returns>Chainable.(LinkedList<Base>, this)</returns>
public LinkedList<Base> throwsNulls()
{
if (!this.hasNullValues)
{
this.hasNullValues = true;
}
this.throwNullError = true;
return this;
}
/// <summary>
/// Iff duplicates not allowed, searches for value in list. Throws error if duplicate found.
/// Creates a new node at the end of the list, then links it to the head node.
/// O(length) [if hasDuplicates()]
/// O(1) [if else]
/// Chainable
/// </summary>
/// <param name="value">Value stored at the new node in the list</param>
/// <returns>Chainable.(LinkedList<Base>, this)</returns>
public LinkedList<Base> add(Base value)
{
if (!duplicates)
{
if (search(value) != null)
{
throw new Exception("Value already exists in the linked list.");
}
}
if (!this.hasNullValues && value != null)
{
if (this.throwNullError)
{
throw new Exception("Cannot insert null values");
}
else
{
return this;
}
}
Node newNode = new Node(value);
this.head.getPrev().setNext(newNode);
this.head.setPrev(newNode);
return this;
}
/// <summary>
/// Iterates through the list until first such node for with a matching value is found.
/// Returns null if no matches found.
/// Use searchAll to find duplicates.
/// O(length)
/// </summary>
/// <param name="value">The value to be searched for.</param>
/// <returns>First node with the desired value(Node?)</returns>
public Node search(Base value)
{
Node temp = this.head.getNext();
while (!temp.getVal().Equals(value))
{
if (temp.Equals(this.head))
{
return null;
}
temp = temp.getNext();
}
return temp;
}
/// <summary>
/// If value doesn't exist in the list, throws an exception.
/// Deletes the first node found with the chosen value.
/// Use DeleteAll to delete all instances.
/// Chainable.
/// O(length)
/// </summary>
/// <param name="value">Value to be removed from the list.</param>
/// <returns>Chainable.(LinkedList<Base>, this)</returns>
public LinkedList<Base> delete(Base value)
{
try{
return delete(search(value));
}
catch(Exception e){
throw new Exception("Node to be deleted not found");
}
}
/// <summary>
/// Removes all pointers to the passed node.
/// O(1)
/// </summary>
/// <param name="tbd">The node to be deleted.</param>
/// <returns>Chainable.(LinkedList<Base>, this)</returns>
public LinkedList<Base> delete(Node tbd)
{
if (tbd.Equals(this.head))
{
throw new Exception("Cannot delete head node");
}
else
{
tbd.getPrev().setNext(tbd.getNext());
tbd.getNext().setPrev(tbd.getPrev());
}
return this;
}
/// <summary>
/// Returns a LinkedList of all nodes containing the desired value.
/// O(length)
/// </summary>
/// <param name="value">The value to be found.</param>
/// <returns>A LinkedList of Nodes with matching values.(LinkedList<Node>)</returns>
public LinkedList<Node> searchAll(Base value)
{
LinkedList<Node> returnList = new LinkedList<Node>();
Node temp = this.head.getNext();
while (!temp.Equals(this.head))
{
if (temp.getVal().Equals(value))
{
returnList.add(temp);
}
temp = temp.getNext();
}
return returnList;
}
/// <summary>
/// Returns the first Node in the Linked List.
/// O()
/// </summary>
/// <returns>First non-head node in the list.(Node)</returns>
public Node firstOrDefault()
{
return this.head.getNext();
}
/// <summary>
/// Returns the value of the first node in the list.
/// O(1)
/// </summary>
/// <returns>FIrst non-head </returns>
public Base firstVal()
{
return this.head.getNext().getVal();
}
/// <summary>
/// Gets the last node in the linked list.
/// O(1)
/// </summary>
/// <returns>The last node in the linked list.(Node)</returns>
public Node tail()
{
return this.head.getPrev();
}
/// <summary>
/// Returns the value of the last node in the linked list.
/// O(1)
/// </summary>
/// <returns>VThe value of the tail node.(Base)</returns>
public Base tailVal()
{
return this.head.getPrev().getVal();
}
public static void Main()
{
LinkedLis t<Int32> mine = new LinkedList<Int32>();
}
}
}
但是，它会在Int32下面显示红色文字，说＆＃34;类型＆＃39; int＆＃39;必须是参考类型才能将其用作参数＆＃39; Base＆＃39;在通用类型或方法---这---。
告诉我您是否希望我删除评论，我不确定这是否会使解决更难或更容易。
答案 0 :(得分：2)
因为您将Base类型的约束声明为类（reference type）：
public class LinkedList<Base> where Base : class
它完全禁止使用Int32，因为它是value type并且是different来自所需的引用类型。
new LinkedList<Int32>()
因此，要解决此特定问题，您需要为整数值创建一个包装类。
在此之前，请检查您的意图，以便在链接列表中存储任何类型。这样做，您将剥夺C＃作为强类型语言的所有优点。
正如前面提到的，除非你把这段代码写成纯粹的学术练习，否则你应该使用现有的.NET LinkedList，如果你需要更多的功能，可以扩展/继承它。
更新：我认为不言而喻，但为了清楚起见，请不要忘记Nullable是struct，而不是{{1}所以你不能使用＆＃34;作弊＆＃34;喜欢int？。