Question

我一直在尝试在处理JSON数据时收到的数据中返回某个值，但我似乎无法获得特定值。我只能得到所有的信息。这里有更详细的问题：

代码：

class ViewController: UIViewController, NSURLConnectionDelegate {

lazy var data = NSMutableData()

override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.
}

override func viewWillAppear(animated: Bool) {
    super.viewWillAppear(animated)
    startConnection()
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

func startConnection(){
    let urlPath: String = "https://na.api.pvp.net/api/lol/na/v1.4/summoner/by-name/soon2challenger?api_key=(removed my private API key for obvious reasons)"
    var url: NSURL = NSURL(string: urlPath)!
    var request: NSURLRequest = NSURLRequest(URL: url)
    var connection: NSURLConnection = NSURLConnection(request: request, delegate: self, startImmediately: false)!
    connection.start()
}

func connection(connection: NSURLConnection!, didReceiveData data: NSData!){
    self.data.appendData(data)
}

func buttonAction(sender: UIButton!){
    startConnection()
}

func connectionDidFinishLoading(connection: NSURLConnection!) {
    var err: NSError
    // throwing an error on the line below (can't figure out where the error message is)
    var jsonResult: NSDictionary = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: nil) as! NSDictionary
    println(jsonResult)
  }
}

代码工作正常。这是我得到的结果。

{
soon2challenger =     {
    id = 43993167;
    name = soon2challenger;
    profileIconId = 844;
    revisionDate = 1435549418000;
    summonerLevel = 30;
   };
}

问题在于，当我想从列表中返回某个值时，就像在id中一样，我似乎无法做到这一点。我尝试过println（jsonResult [＆＃34; id＆＃34;]），但这只会导致nil。

如何从列表中返回某个值？防爆。 id，name，profileIconId

Answer 1

尝试使用objectForKey，如下所示：

let inside = jsonResult.objectForKey("soon2challenger")

现在您已经解压缩了soon2challenger对象。然后，您可以轻松获得值：

print(include.objectForKey("id"))

Answer 2

您正在尝试访问子数组中的值。以前的海报是正确的;获取子数组后，您可以使用数组[＆＃34; id＆＃34;];

无法返回正确的JSON值

2 个答案: