sort array with true values first

Question

How can I sort an array so all objects with a value of true for the key can_friend will be first in the array?

var people = [{can_friend: true}, {can_friend: false}, {can_friend: true}]

would get sorted to

var desired_result = [{can_friend: true}, {can_friend: true}, {can_friend: false}]

Answer 1

With a standard sort using can_friend as criterion and the fact that booleans convert to 1 and 0 on subtraction:

people.sort(function (a, b) { return b.can_friend - a.can_friend; });

Answer 2

由于问题标有underscore.js，因此这是使用它的解决方案：

var sorted = _.sortBy( people, function(element){ return element.can_friend ? 0 : 1; } );

或更短：

var sorted = _.sortBy( people, function(e){ return !e.can_friend; } );

或使用ES6箭头函数语法：

var sorted = _.sortBy( people, e=>!e.can_friend );

Answer 3

Try this:

people.sort(function(val1, val2) {
  if (val1.can_friend && !val2.can_friend) return -1;
  else if (!val1.can_friend && val2.can_friend) return 1;
  else return 0;
});

Answer 4

This is in plain JS, which works for the situation perfectly:

people.sort(function(item) {
  return !item.can_friend;
});