Question

$data= array();
$data[1]= Trial" Broker;
$data[2]= some'y Bank .
$data[3]=United ;States

My array contains lots of single, double quotes and semicolons in between the value and I don't want them.

This might help: replace them is enough.

I'm looking for the simplest function to perform this task please.

Answer 1

You can iterate over the array and do a simple preg replace to strip out all characters other than a-z and 0-9

for ($i=0; $i < count($data); $i++) {
    $data[$i] = preg_replace("/[^A-Za-z0-9?!]/", "", $data[$i]);
}

Be sure to set $i to the starting number of your array within the for loop above

$i=1; // in your given example

$i=0; // usually by default an array will start from 0

Answer 2

尝试

#include<stdlib.h>
#include<string.h>
#include<stdio.h>
#include<ctype.h>
#include<locale.h>

int main () {
setlocale (LC_ALL,"UTF8");
FILE *puntafile;
char c, nome[30];

//Choosing file name
printf("Insert file name (Max 25 characters): ");
gets(nome);

while(strlen(nome) > 25)
 {
    printf("Too much long name!\n");
    printf("Insert file name (Max 25 characters): ");
    gets(nome);
 } 

//creation file name .vbs
char est[4];
strcpy (est,".vbs");
strcat (nome,est);

char testo[100];

//create the empty file
puntafile = fopen(nome,"w+");

//Insert the message
printf("Insert the note text (Max 100 characters): ");
gets(testo);

while(strlen(testo) > 100)
 {
    printf("Too much long text!\n");
    printf("Insert the note text (Max 100 characters): ");
    gets(testo);

 } 

//writing in the file...
char note[150];

//start text
strcpy(note,"msgbox \"");

//add the note text
strcat(note,testo);

//ending text
char closing[20];
strcpy(closing,"\" , \"6\" , \"Note\"");
strcat(note,closing);    

//writing all in the .vbs file  
fprintf(puntafile,"%s",note);


//end and close
printf("Note created!\n");
fclose(puntafile);
system("PAUSE");
}

How do I delete/replace all single, double quotes and semicolons from the Array values

2 个答案: