我不是为什么我的Google图表没有呈现而是显示
我还注意到我在控制台上收到此错误消息。
未捕获的TypeError:无法读取未定义的属性“危险”
然后,我检查了我的JSON文件,危险就在那里。它指的是哪个危险?
'use strict';
define(['jquery'], function($) {
$(function() {
var danger = $('#pc-danger');
var warning = $('#pc-warning');
var success = $('#pc-success');
var danger_list = $('#pc-danger-list');
var warning_list = $('#pc-warning-list');
var success_list = $('#pc-success-list');
var basePath = "/BIM/resources/js/reports/student/section-exercise/";
$.ajax({
url: basePath + "data.json",
type: "GET",
dataType : "json",
success: function( objects ) {
function updateInfo(x) {
danger.html(objects[x].danger);
warning.html(objects[x].warning);
success.html(objects[x].success);
danger_list.html(objects[x].danger_list);
warning_list.html(objects[x].warning_list);
success_list.html(objects[x].success_list);
}
// Load the Visualization API and the piechart package.
google.load("visualization", "1", {packages:["corechart"]});
google.setOnLoadCallback(drawChart());
function drawChart() {
var options = {
width: 160,
height: 160,
chartArea: {
left: 10,
top: 20,
width: "100%",
height: "100%"
},
colors: ['#F46E4E', '#F9C262' , '#ADB55E',],
legend: 'none',
enableInteractivity: false,
pieSliceText: 'none',
};
var data = {};
var chart = {};
for (var object in objects) {
var total = objects[object].danger + objects[object].warning + objects[object].success ;
data[object] = google.visualization.arrayToDataTable([
['Piechart' , 'Number of Skills'],
['danger' , ( objects[object].danger/total ) * 100 ],
['warning' , ( objects[object].warning/total ) * 100 ],
['success' , ( objects[object].success/total ) * 100 ],
]);
object = object.toLowerCase();
// piechart object
var $el = $('#sa-piechart-' + object );
// button
var button = $('.sa-report-btn-'+ object );
// append
var $el = $('#sa-piechart-' + object ).length ? $('#sa-piechart-' + object ) : $('<div id="sa-piechart-' + object +'"></div>').appendTo($('#sa-piechart-'+ object ));
chart[object] = new google.visualization.PieChart($el[0]);
chart[object].draw(data[object]);
// attach click handler to the button
button.click(function() {
updateInfo(object);
chart[object].draw(data[object]);
});
}
}
},
error: function( xhr, status, errorThrown ) {
alert( "Sorry, there was a problem!" );
console.log( "Error: " + errorThrown );
console.log( "Status: " + status );
console.dir( xhr );
},
});
});
});
{
"A": {
"report_type": "chapter test",
"section_num": "2",
"assignment": "algebra 1",
"date": "2/10/2015",
"correct_num": "15",
"avg_score": "89",
"danger": "5",
"danger_list": "5,10,15,19,23",
"warning": "8",
"warning_list": "3,7,11,13,14,16,21,22",
"success": "12",
"success_list": "1,2,4,6,8,9,12,17,18,20,24,25"
},
"B": {
"report_type": "section exercise",
"section_num": "2.2",
"assignment": "algebra 1",
"date": "2/09/2015",
"correct_num": "11",
"avg_score": "44",
"danger": "12",
"danger_list": "11,12,13,14,15,16,17,18,19,20,3,4",
"warning": "2",
"warning_list": "1,2",
"success": "11",
"success_list": "21,21,23,24,25,5,6,7,8,9,10"
},
"C": {
"report_type": "test",
"section_num": "1",
"assignment": "algebra 1",
"date": "1/10/2015",
"correct_num": "15",
"avg_score": "75",
"danger": "0",
"danger_list": "",
"warning": "10",
"warning_list": "1,2,3,4,5,6,7,8,9,10",
"success": "15",
"success_list": "11,12,13,14,15,16,17,18,19,20,21,22,23,24,25"
},
"D": {
"report_type": "practice test",
"section_num": "1",
"assignment": "algebra 1",
"date": "1/09/2015",
"correct_num": "15",
"avg_score": "79",
"danger": "5",
"danger_list": "1,2,3,4,5",
"warning": "0",
"warning_list": "",
"success": "20",
"success_list": "6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25"
}
}
任何帮助/提示/建议对我来说意义重大。
谢谢!
答案 0 :(得分:1)
您正在将DataTable
推送到data[object]
A,B,C..
,之后您将此行转移到lowerCase: -
object = object.toLowerCase();
所以在那之后当你得到那个对象时,它在这一行中返回null: -
chart[object].draw(data[object]);
所以你只需要删除这一行: -
object = object.toLowerCase();
这里是demo(我只使用一个div进行演示) Demo
希望这会对你有所帮助。