我有一个谷歌地图,它从数据库中提取信息,并用标记,名称,地址等填充它。在同一个数据库中有一个名为“slug”的URL。我想让每个标记的名称/地址弹出窗口是一个可点击的链接,带你到“slug”。
到目前为止,这是代码:
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Google Maps AJAX + mySQL/PHP Example</title>
<script src="http://maps.google.com/maps/api/js?sensor=false" type="text/javascript"></script>
<script type="text/javascript">
//<![CDATA[
var customIcons = {
restaurant: {
icon: 'http://labs.google.com/ridefinder/images/mm_20_blue.png',
shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
},
bar: {
icon: 'http://labs.google.com/ridefinder/images/mm_20_red.png',
shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
}
};
function load() {
var map = new google.maps.Map(document.getElementById("map"), {
center: new google.maps.LatLng(47.6145, -122.3418),
zoom: 5,
mapTypeId: 'roadmap'
});
var infoWindow = new google.maps.InfoWindow;
// Change this depending on the name of your PHP file
downloadUrl("phpsqlsearch_genxml.php", function(data) {
var xml = data.responseXML;
var markers = xml.documentElement.getElementsByTagName("marker");
for (var i = 0; i < markers.length; i++) {
var first = markers[i].getAttribute("first");
var last = markers[i].getAttribute("last");
var line_1 = markers[i].getAttribute("line_1");
var line_2 = markers[i].getAttribute("line_2");
var line_3 = markers[i].getAttribute("line_3");
var city = markers[i].getAttribute("city");
var state = markers[i].getAttribute("state");
var zipcode = markers[i].getAttribute("zipcode");
var address = markers[i].getAttribute("address");
var type = markers[i].getAttribute("type");
var point = new google.maps.LatLng(
parseFloat(markers[i].getAttribute("lat")),
parseFloat(markers[i].getAttribute("lng")));
var html = "<b>" + first + "\xa0" + last + "</b> <br/>" + line_1 + "<br/>" + (line_2 ? line_2 + "<br/>" : "") + (line_3 ? line_3 + "<br/>" : "") + city + "\xa0" + "," + state + "\xa0" + zipcode;
console.log(html);
var icon = customIcons[type] || {};
var marker = new google.maps.Marker({
map: map,
position: point,
icon: icon.icon,
shadow: icon.shadow
});
bindInfoWindow(marker, map, infoWindow, html);
}
});
}
function bindInfoWindow(marker, map, infoWindow, html) {
google.maps.event.addListener(marker, 'click', function() {
infoWindow.setContent(html);
infoWindow.open(map, marker);
});
}
function downloadUrl(url, callback) {
var request = window.ActiveXObject ?
new ActiveXObject('Microsoft.XMLHTTP') :
new XMLHttpRequest;
request.onreadystatechange = function() {
if (request.readyState == 4) {
request.onreadystatechange = doNothing;
callback(request, request.status);
}
};
request.open('GET', url, true);
request.send(null);
}
function doNothing() {}
//]]>
</script>
</head>
<body onload="load()">
<div id="map" style="width: 100%; height: 100%"></div>
</body>
</html>
答案 0 :(得分:0)
之后:
var html = "<b>" + first + "\xa0" + last + "</b> <br/>" + line_1 + "<br/>" + (line_2 ? line_2 + "<br/>" : "") + (line_3 ? line_3 + "<br/>" : "") + city + "\xa0" + "," + state + "\xa0" + zipcode;
添加:
var slug = markers[i].getAttribute("slug");
html = "<a href='" + slug + "'>" + html + "</a>";
这将使弹出窗口中的所有文本成为可点击的链接