Question

刚开始学习Selenium。所以网站的检查要素如下：

<select ng-model="selectedFacility" ng-options="facility as facility.name for facility in facilities" ng-change="afterSelectingFacility()" class="ng-pristine ng-valid ng-touched"> <option> </option> </select>

我使用以下代码访问元素：

Select facility = new Select(driver.findElement(By.cssSelector("input[class=('ng - pristine ng - valid ng-touched']")));

但是我收到以下错误：

org.openqa.selenium.InvalidSelectorException: The given selector input[class=('ng - pristine ng - valid ng-touched'] is either invalid or does not result in a WebElement. The following error occurred: InvalidSelectorError: An invalid or illegal selector was specified

我已经浏览了stackoverflow中的一些帖子，但他们没有帮助我。

Answer 1

使用Css按类选择时，为什么不使用正确的语法？

By.cssSelector("select.ng-pristine.ng-valid.ng-touched")

您也可以使用xpath：

By.xpath("//select[@ng-model='selectedFacility' and @class='ng-pristine ng-valid ng-touched']");

Answer 2

你的选择器应该是

By.cssSelector("select[class='ng - pristine ng - valid ng-touched']")



Select facility =new Select(driver.findElement(By.cssSelector("select[class='ng - pristine ng - valid ng-touched']")));

EDIT-I

试试这个

By.cssSelector("select[ng-model='selectedFacility']")

使用selenium webdriver和intellij时出现InvalidSelectorException

2 个答案: