Question

在定时器关闭之前，while循环后定义的div和按钮都不可见。我不知道是什么问题。我在php之外尝试了它，但它仍然没有显示任何内容。在添加这个PHP代码之前，一切都运行良好，以显示从数据库中随机选择的一些不同的问题。有人请帮帮我。我是php的新手。非常感谢。

<?php

$record=array(); //creating array to keep record of Q_ID of questions

for($count=1;$count <= $NoOfQuestion;$count++)// to display $NoOfQuestion number of questions
{
    while(1)
    {
        $sql=mysql_query("select * from questions order by RAND()");
        $result = mysql_fetch_array($sql);
        $temp=0;
        if(count($record)>=1)
           {
              for($i=1;$i<=$count;$i++)
              {
                  if($record[$i]==$result['Q_ID'])
                  $temp++;
              }
           }
       if($temp==0)
           {
              $text ='Question '.$count. '. '.$result['Question'];

              echo $text;
              return 0;
           }
       else
           return 1;
    }
    echo'</div>';
    echo'<div id="option"></div>';
    echo'<div id="buton">'; 
    echo'<input type="submit" name="Previous" value="previous" id="previous"/>';
    echo'<input type="submit" name="Next" value="next" id="next"/>'; 
    echo'<input type="submit" name="Review" value="review" id="review"/>'; 
    echo'<input type="submit" name="Submit" value="submit" id="submit"/>';

    echo'</div>';
    echo'<div id="div3">3</div>';
    echo'</div>';

    echo'</form>';
}    

?>

Answer 1

修改你的代码......

echo'<div id="option"></div>';
echo'<div id="buton">'; 
echo'<input type="submit" name="Previous" value="previous" id="previous"/>';
echo'<input type="submit" name="Next" value="next" id="next"/>'; 
echo'<input type="submit" name="Review" value="review" id="review"/>'; 
echo'<input type="submit" name="Submit" value="submit" id="submit"/>';

echo'</div>';
echo'<div id="div3">3</div>';

Answer 2

尝试

<?php

$record=array(); //creating array to keep record of Q_ID of questions

for($count=1;$count <= $NoOfQuestion;$count++)// to display $NoOfQuestion number of questions
{
    while(1)
    {
        $sql=mysql_query("select * from questions order by RAND()");
        $result = mysql_fetch_array($sql);
        $temp=0;
        if(count($record)>=1)
        {
            for($i=1;$i<=$count;$i++)
            {
                if($record[$i]==$result['Q_ID'])
                $temp++;
            }
        }

        if($temp==0)
        {
            $text ='Question '.$count. '. '.$result['Question'];

            echo $text;
            return 0;
        }
        else
            return 1;
    }
}

    echo '</div>';
    echo '<div id="option"></div>';
    echo '<div id="buton">'; 
    echo '<input type="submit" name="Previous" value="previous" id="previous"/>';
    echo '<input type="submit" name="Next" value="next" id="next"/>'; 
    echo '<input type="submit" name="Review" value="review" id="review"/>'; 
    echo '<input type="submit" name="Submit" value="submit" id="submit"/>';

    echo '</div>';
    echo '<div id="div3">3</div>';
    echo '</div>';

    echo '</form>';
?>

在php中定义的按钮是不可见的

2 个答案: