输出

Question

我有一张像

这样的表格

colA    colB    colC
A        10      1
A        20      2
A        30      3
B        10      1
B        20      2

我想要一个像这样的输出

ColA  colB  colC
A      60    1,2,3
B      30    1,2

有人可以告诉我如何使用和不使用函数，以及在PL / SQL中吗？

Answer 1

这是你需要的sql。注意：它只能在oracle 11g R2上运行。

   with tab as( 
    select 'A' col1,10 col2,1 col3 from dual union all
    select 'A' col1,20 col2,2 col3 from dual union all
    select 'A' col1,30 col2,3 col3 from dual union all
    select 'B' col1,10 col2,1 col3 from dual union all
    select 'B' col1,20 col2,2 col3 from dual )
    select  col1, sum(col2),listagg(col3,',') WITHIN GROUP (ORDER BY col3) AS col3_list 
    from tab group by col1

Answer 2

假设您的表名是标签

with tab1(col1, col2) as (
  select colA, sum(colB) 
  from tab group by colA
),
tab2(col1, col2) as (
  select colA, LISTAGG(TO_CHAR(colC),',')
  WITHIN GROUP (ORDER BY colC)
  from tab group by colA
)
select a.col1, a.col2, b.col2 
from tab1 a, tab2 b 
where a.col1 = b.col1

输出：

COL1  COL2  COL2
A     60    1,2,3
B     30    1,2

有关LISTAGG link

的详细信息

此link解释了multiple with clause

或者简单地说;

select colA, sum(colB) colB,LISTAGG(TO_CHAR(colC),',')
  WITHIN GROUP (ORDER BY colC)
  from tab group by colA

Answer 3

Probably this may the easiest solution syntactically :)

SELECT COLA,
  SUM(COLB),
  WMSYS.WM_CONCAT(COLC)
FROM
  (SELECT 'A' cola,10 AS colb,1 AS colc FROM dual
  UNION
  SELECT 'A' cola,20 AS colb,2 AS colc FROM dual
  UNION
  SELECT 'A' cola,30 AS colb,3 AS colc FROM dual
  UNION
  SELECT 'B' cola,10 AS colb,1 AS colc FROM dual
  UNION
  SELECT 'B' cola,20 AS colb,2 AS colc FROM dual
  )
GROUP BY COLA ;

输出

COLA SUM（COLB）WMSYS.WM_CONCAT（COLC） A 60 1,2,3

SQL查询以获取分组总和和连接列表，最好不使用函数

3 个答案:

输出

B 30 1,2