这里的目标是实时创建压缩的mp4视频文件。 我将屏幕截图保存为硬盘上的位图类型。 我想创建mp4文件并实时压缩mp4视频文件。
问题是我看到的视频文件看起来很奇怪。 结果如下:Strange Video File
我使用带参数的ffmpeg的类。
using System;
using System.Windows.Forms;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Drawing;
using System.IO.Pipes;
using System.Runtime.InteropServices;
using System.Diagnostics;
using System.IO;
using DannyGeneral;
namespace Youtube_Manager
{
class Ffmpeg
{
NamedPipeServerStream p;
String pipename = "mytestpipe";
System.Diagnostics.Process process;
string ffmpegFileName = "ffmpeg.exe";
string workingDirectory;
public Ffmpeg()
{
workingDirectory = Path.GetDirectoryName(Application.ExecutablePath);
Logger.Write("workingDirectory: " + workingDirectory);
if (!Directory.Exists(workingDirectory))
{
Directory.CreateDirectory(workingDirectory);
}
ffmpegFileName = Path.Combine(workingDirectory, ffmpegFileName);
Logger.Write("FfmpegFilename: " + ffmpegFileName);
}
public void Start(string pathFileName, int BitmapRate)
{
try
{
string outPath = pathFileName;
p = new NamedPipeServerStream(pipename, PipeDirection.Out, 1, PipeTransmissionMode.Byte);
ProcessStartInfo psi = new ProcessStartInfo();
psi.WindowStyle = ProcessWindowStyle.Hidden;
psi.UseShellExecute = false;
psi.CreateNoWindow = false;
psi.FileName = ffmpegFileName;
psi.WorkingDirectory = workingDirectory;
psi.Arguments = @"-f rawvideo -pix_fmt yuv420p -video_size 1920x1080 -i \\.\pipe\mytestpipe -map 0 -c:v mpeg4 -r " + BitmapRate + " " + outPath;
//psi.Arguments = @"-framerate 1/5 -i -c:v libx264 -r 30 -pix_fmt yuv420p \\.\pipe\mytestpipe -map 0 -c:v mpeg4 -r" + BitmapRate + " " + outPath;
process = Process.Start(psi);
process.EnableRaisingEvents = false;
psi.RedirectStandardError = true;
p.WaitForConnection();
}
catch (Exception err)
{
Logger.Write("Exception Error: " + err.ToString());
}
}
public void PushFrame(Bitmap bmp)
{
try
{
int length;
// Lock the bitmap's bits.
//bmp = new Bitmap(1920, 1080);
Rectangle rect = new Rectangle(0, 0, bmp.Width, bmp.Height);
//Rectangle rect = new Rectangle(0, 0, 1280, 720);
System.Drawing.Imaging.BitmapData bmpData =
bmp.LockBits(rect, System.Drawing.Imaging.ImageLockMode.ReadOnly,
bmp.PixelFormat);
int absStride = Math.Abs(bmpData.Stride);
// Get the address of the first line.
IntPtr ptr = bmpData.Scan0;
// Declare an array to hold the bytes of the bitmap.
//length = 3 * bmp.Width * bmp.Height;
length = absStride * bmpData.Height;
byte[] rgbValues = new byte[length];
//Marshal.Copy(ptr, rgbValues, 0, length);
int j = bmp.Height - 1;
for (int i = 0; i < bmp.Height; i++)
{
IntPtr pointer = new IntPtr(bmpData.Scan0.ToInt32() + (bmpData.Stride * j));
System.Runtime.InteropServices.Marshal.Copy(pointer, rgbValues, absStride * (bmp.Height - i - 1), absStride);
j--;
}
p.Write(rgbValues, 0, length);
bmp.UnlockBits(bmpData);
}
catch(Exception err)
{
Logger.Write("Error: " + err.ToString());
}
}
public void Close()
{
p.Close();
}
}
}
然后我在这个类中使用PushFrame方法:
public Bitmap GetScreenShot(string folder, string name)
{
_screenShot = new Bitmap(GetScreen());
System.GC.Collect();
System.GC.WaitForPendingFinalizers();
string ingName = folder + name + images.counter.ToString("D6") + ".bmp";
_screenShot.Save(ingName,System.Drawing.Imaging.ImageFormat.Bmp);
fmpeg.PushFrame(_screenShot);
_screenShot.Dispose();
return _screenShot;
}
硬盘上的位图很好我可以编辑/打开看到它们。 当使用命令提示符并手动键入ffmpeg命令时,它会压缩并创建一个mp4视频文件。
但是当我使用Ffmpeg类时,我使用PushFrame方法创建了这个奇怪的视频文件。
这是我的OneDrive的链接,其中包含10个用于测试的屏幕截图图像文件:
播放视频文件时,视频文件中的示例截图: 看起来很不稳定。硬盘上的位图每个都是1920x1080,位深度为32
但它在视频文件中看起来不像那样:
这是我使用的论据:
psi.Arguments = @"-f rawvideo -vcodec rawvideo -pix_fmt rgb24 -video_size 1920x1080 -i \\.\pipe\mytestpipe -map 0 -c:v mpeg4 -r " + BitmapRate + " " + outPath;
视频尺寸非常小1.24 MB
答案 0 :(得分:0)
You need to set both, -f rawvideo
which indicates the kind of container you are using for your input, and -vcodec rawvideo
which does the same for the video data you are pushing to ffmpeg
. Otherwise, ffmpeg will try to detect the type of container you are using, and that probably won't work as expected.
Also, as @Ely commented, you need to set the -pix_fmt rgb24
, as that is the format of the images you are sending.
Also note that you can get better information about what ffmpeg is doing by using the -v debug
parameter.