我有一个已删除的文件存档数据库，用于存储已删除文件的ID，我希望管理员能够还原文件（以及链接文件的相同ID）。我不想将identity_insert从整个表中删除，因为一个增量很有效。在我的TBL_Content存储过程的插入中，我有类似的东西
set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
SET IDENTITY_INSERT tbl_content ON
GO
ALTER procedure [dbo].[spInsertDeletedIntoTBLContent]
@ContentID int,
...insert command...
SET IDENTITY_INSERT tbl_content OFF
但我一直得到同样的错误：
无法在表中插入identity列的显式值 当IDENTITY_INSERT设置为OFF时，“TBL_Content”。
任何帮助？
答案 0 :(得分：149)
您是否应该在存储过程中将身份插入设置为on？看起来您只在更改存储过程时将其设置为on，而不是在实际调用它时。尝试：
ALTER procedure [dbo].[spInsertDeletedIntoTBLContent]
@ContentID int,
SET IDENTITY_INSERT tbl_content ON
...insert command...
SET IDENTITY_INSERT tbl_content OFF
GO
答案 1 :(得分：15)
你不应该将identity_Insert设置为ON，插入记录然后将其关闭吗？
像这样：
set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
SET IDENTITY_INSERT tbl_content ON
GO
ALTER procedure [dbo].[spInsertDeletedIntoTBLContent]
@ContentID int,
SET IDENTITY_INSERT tbl_content ON
...insert command...
SET IDENTITY_INSERT tbl_content OFF
答案 2 :(得分：12)
我认为需要在单个查询批处理中完成。基本上，GO语句将您的命令分成多个批次并导致问题。将其更改为：
SET IDENTITY_INSERT tbl_content ON
/* GO */
...insert command...
SET IDENTITY_INSERT tbl_content OFF
GO
答案 3 :(得分：9)
<强>提醒
SQL Server只允许一个表将IDENTITY_INSERT属性设置为ON。
这不起作用：
<?php
include_once 'psl-config.php';
function sec_session_start() {
$session_name = 'sec_session_id'; // Set a custom session name
$secure = SECURE;
// This stops JavaScript being able to access the session id.
$httponly = true;
// Forces sessions to only use cookies.
if (ini_set('session.use_only_cookies', 1) === FALSE) {
header("Location: ../error.php?err=Could not initiate a safe session (ini_set)");
exit();
}
// Gets current cookies params.
$cookieParams = session_get_cookie_params();
session_set_cookie_params($cookieParams["lifetime"],
$cookieParams["path"],
$cookieParams["domain"],
$secure,
$httponly);
// Sets the session name to the one set above.
session_name($session_name);
session_start(); // Start the PHP session
session_regenerate_id(true); // regenerated the session, delete the old one.
}
function login($username, $password, $mysqli) {
// Using prepared statements means that SQL injection is not possible.
if ($stmt = $mysqli->prepare("SELECT id, email, password, salt
FROM members
WHERE username = ?
LIMIT 1")) {
$stmt->bind_param('s', $username); // Bind "$username" to parameter.
$stmt->execute(); // Execute the prepared query.
$stmt->store_result();
// get variables from result.
$stmt->bind_result($user_id, $email, $db_password, $salt);
$stmt->fetch();
// hash the password with the unique salt.
$password = hash('sha512', $password . $salt);
if ($stmt->num_rows == 1) {
// If the user exists we check if the account is locked
// from too many login attempts
if (checkbrute($user_id, $mysqli) == true) {
// Account is locked
// Send an email to user saying their account is locked
return false;
} else {
// Check if the password in the database matches
// the password the user submitted.
if ($db_password == $password) {
// Password is correct!
// Get the user-agent string of the user.
$user_browser = $_SERVER['HTTP_USER_AGENT'];
// XSS protection as we might print this value
$user_id = preg_replace("/[^0-9]+/", "", $user_id);
$_SESSION['user_id'] = $user_id;
// XSS protection as we might print this value
$username = preg_replace("/[^a-zA-Z0-9_\-]+/",
"",
$username);
$_SESSION['username'] = $username;
$_SESSION['login_string'] = hash('sha512',
$password . $user_browser);
// Login successful.
return true;
} else {
// Password is not correct
// We record this attempt in the database
$now = time();
$mysqli->query("INSERT INTO login_attempts(user_id, time)
VALUES ('$user_id', '$now')");
return false;
}
}
} else {
// No user exists.
return false;
}
}
}
function checkbrute($user_id, $mysqli) {
// Get timestamp of current time
$now = time();
// All login attempts are counted from the past 2 hours.
$valid_attempts = $now - (2 * 60 * 60);
if ($stmt = $mysqli->prepare("SELECT time
FROM login_attempts
WHERE user_id = ?
AND time > '$valid_attempts'")) {
$stmt->bind_param('i', $user_id);
// Execute the prepared query.
$stmt->execute();
$stmt->store_result();
// If there have been more than 10 failed logins
if ($stmt->num_rows > 10) {
return true;
} else {
return false;
}
}
}
function login_check($mysqli) {
// Check if all session variables are set
if (isset($_SESSION['user_id'],
$_SESSION['username'],
$_SESSION['login_string'])) {
$user_id = $_SESSION['user_id'];
$login_string = $_SESSION['login_string'];
$username = $_SESSION['username'];
// Get the user-agent string of the user.
$user_browser = $_SERVER['HTTP_USER_AGENT'];
if ($stmt = $mysqli->prepare("SELECT password
FROM members
WHERE id = ? LIMIT 1")) {
// Bind "$user_id" to parameter.
$stmt->bind_param('i', $user_id);
$stmt->execute(); // Execute the prepared query.
$stmt->store_result();
if ($stmt->num_rows == 1) {
// If the user exists get variables from result.
$stmt->bind_result($password);
$stmt->fetch();
$login_check = hash('sha512', $password . $user_browser);
if ($login_check == $login_string) {
// Logged In!!!!
return true;
} else {
// Not logged in
return false;
}
} else {
// Not logged in
return false;
}
} else {
// Not logged in
return false;
}
} else {
// Not logged in
return false;
}
}
function esc_url($url) {
if ('' == $url) {
return $url;
}
$url = preg_replace('|[^a-z0-9-~+_.?#=!&;,/:%@$\|*\'()\\x80-\\xff]|i', '', $url);
$strip = array('%0d', '%0a', '%0D', '%0A');
$url = (string) $url;
$count = 1;
while ($count) {
$url = str_replace($strip, '', $url, $count);
}
$url = str_replace(';//', '://', $url);
$url = htmlentities($url);
$url = str_replace('&', '&', $url);
$url = str_replace("'", ''', $url);
if ($url[0] !== '/') {
// We're only interested in relative links from $_SERVER['PHP_SELF']
return '';
} else {
return $url;
}
}
相反：
SET IDENTITY_INSERT TableA ON
SET IDENTITY_INSERT TableB ON
... INSERT ON TableA ...
... INSERT ON TableB ...
SET IDENTITY_INSERT TableA OFF
SET IDENTITY_INSERT TableB OFF
答案 4 :(得分：5)
参考：http://technet.microsoft.com/en-us/library/aa259221%28v=sql.80%29.aspx
我的表名为Genre，其中包含3列Id，Name和SortOrder
我使用的代码如下：
SET IDENTITY_INSERT Genre ON
INSERT INTO Genre(Id, Name, SortOrder)VALUES (12,'Moody Blues', 20)
答案 5 :(得分：3)
在查询
上方添加此行SET IDENTITY_INSERT tbl_content ON
答案 6 :(得分：0)
同时添加设置
SET IDENTITY_INSERT Genre ON
INSERT INTO Genre(Id, Name, SortOrder)VALUES (12,'Moody Blues', 20)
SET IDENTITY_INSERT Genre OFF