Question

我试图找出如何在拖放表中存储user_id值，并在将项目放入新列时传递值。

例如我的代码。我启动了“Owes＆＃39;”中的所有用户。柱。当有人支付时，我想用拖放表将它们移动到适当的列。我正从我的数据库中输出所有这些信息，所以当我从“Owes＆＃39;付款＆＃39;付款＆＃39;我将需要更新数据库中的记录，以便将其保存在拖放表中。

我的桌子就是这样..

 <table class="paymentTable" id="dragTable">
        <tr>
            <th class="thPayment">Paid</th>
            <th class="thPayment">Partially Paid</th>
            <th class="thPayment">Owes</th>
        </tr>
        <tr>
            <td class="tdPayment" id="paid">
                            <div>
            <?php
                if ($paid_name == true) {
                    echo $paid_name;
                } else {
                    echo "No one has paid";
                }
            ?>
                            </div>
            </td>
            <td class="tdPayment" id="partially_paid">
            <div>
            <?php 
                if ($partially_paid__name == true) {
                    echo $partially_paid__name . " - " . $partially_paid_amount;
                } else {
                    echo "No one has made a partial payment";
                }
            ?>  
            </div>
            </td>
            <td class="tdPayment" id="owes">
            <div>
            <?php
                if ($owes_name == true) {
                    echo $owes_name;
                } else {
                    echo "Everyone has paid something";
                }
            ?>  
            </div>
            </td>
        </tr>
    </table>

我像这样拖放表格单元格。

 $(function() {
        $( "#paid, #partially_paid, #owes" ).sortable({
          connectWith: ".tdPayment",
          remove: function(e, ui) {
            var $this = $(this);
            var childs = $this.find('div');
            if (childs.length === 0) {
               $this.text("Nothing");
            }
          },
          receive: function(e, ui) {
            $(this).contents().filter(function() {
                return this.nodeType == 3; //Node.TEXT_NODE
             }).remove();
          },
        }).disableSelection();
      });

我输出值的php是这样的。我要整合php所以它只有一个db表而不是三个，但这传达了我想要做的......

<?php
    //Payment Section

        $con = mysqli_connect("localhost", "root", "", "db");
        $paid_run = mysqli_query($con,"SELECT * FROM paid ORDER BY id DESC");
        $partially_paid_run = mysqli_query($con,"SELECT * FROM partial_payment ORDER BY id DESC");
        $owes_run = mysqli_query($con,"SELECT * FROM owes ORDER BY id DESC");
        $paid_numrows = mysqli_num_rows($paid_run);
        $partially_paid_numrows = mysqli_num_rows($partially_paid_run);
        $owes_numrows = mysqli_num_rows($owes_run);

            if($paid_numrows > 0){
                while($row = mysqli_fetch_assoc($paid_run)){
                    $paid_id = $row['user_id'];
                    $paid_name = $row['name'];
                }
            }

        if($partially_paid_numrows > 0){
                while($row = mysqli_fetch_assoc($partially_paid_run)){
                    $partially_paid_id = $row['user_id'];
                    $partially_paid_name = $row['name'];
                    $partially_paid_amount = $row['payment'];
                }
            }

        if($owes_numrows > 0){
                while($row = mysqli_fetch_assoc($owes_run)){
                    $owes_id = $row['user_id'];
                    $owes_name = $row['name'];
                }
            }
    ?>

如何存储user_id，以便我可以在此拖放表中使用php更新数据库？

如何在数据属性中存储值并使用php传递值

0 个答案: