Question

我有一个带有几个单元格的UITableView，每当我按下其中一个单元格时，我想要转到另一个屏幕。我的代码工作，有点....但有时我会推动细胞两次以便塞！

有谁知道为什么？

func tableView(gamesListTableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
    if (indexPath.row < GamesList.count) {
        self.gameState = GamesList[indexPath.row];
        performSegueWithIdentifier("presentGame", sender: self);
    } else {
        let alert = UIAlertController(title: "Swipe!", message: "Swipe Invite To The Left", preferredStyle: UIAlertControllerStyle.Alert)
        let alertAction = UIAlertAction(title: "OK!", style: UIAlertActionStyle.Default) { (UIAlertAction) -> Void in }
        alert.addAction(alertAction)
        presentViewController(alert, animated: true) { () -> Void in }
    }
}

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject!) {
    if (segue.identifier == "presentGame") {
        var presentGame = segue.destinationViewController as! Game;
        presentGame.gameState = self.gameState;
    }
}

Answer 1

野外存在一个已知的问题，需要使用虚拟dispatch_async调用作为解决方法 - http://openradar.appspot.com/19563577可能在将来的版本中它会消失。以下是具有变通方法的代码的外观：

func tableView(gamesListTableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
    if (indexPath.row < GamesList.count) {
        self.gameState = GamesList[indexPath.row];
        dispatch_async(dispatch_get_main_queue(), {}); //http://openradar.appspot.com/19563577 
        performSegueWithIdentifier("presentGame", sender: self);
    } else {
        let alert = UIAlertController(title: "Swipe!", message: "Swipe Invite To The Left", preferredStyle: UIAlertControllerStyle.Alert)
        let alertAction = UIAlertAction(title: "OK!", style: UIAlertActionStyle.Default) { (UIAlertAction) -> Void in }
        alert.addAction(alertAction)
        presentViewController(alert, animated: true) { () -> Void in }
    }
}

performSegueWithIdentifier并不总是在Swift中工作

1 个答案: