我有一个以下格式的数组,
Array
(
[0] => Array
(
[expense_id] => 7
[type] => frfrf
[mode] => rfr
[amount] => 100
[tran_type] => expense
[date] => 2015-06-29
)
[1] => Array
(
[expense_id] => 8
[type] => frfrf
[mode] => rfr
[amount] => 100
[tran_type] => expense
[date] => 2015-06-29
)
[2] => Array
(
[expense_id] => 9
[type] => frfrf
[mode] => rfr
[amount] => 444
[tran_type] => expense
[date] => 2015-06-29
)
[3] => Array
(
[expense_id] => 10
[type] => frfrf
[mode] => rfr
[amount] => 1000
[tran_type] => income
[date] => 2015-06-29
)
[4] => Array
(
[expense_id] => 5
[type] => frfrf
[mode] => rfr
[amount] => 100
[tran_type] => expense
[date] => 2015-06-01
)
)
我希望根据date
值合并数组,并将其存储为数组,密钥为date
Array
(
[2015-06-29] => Array
(
[0] => Array
(
[expense_id] => 7
[type] => frfrf
[mode] => rfr
[amount] => 100
[tran_type] => expense
[date] => 2015-06-29
)
[1] => Array
(
[expense_id] => 8
[type] => frfrf
[mode] => rfr
[amount] => 100
[tran_type] => expense
[date] => 2015-06-29
)
[2] => Array
(
[expense_id] => 9
[type] => frfrf
[mode] => rfr
[amount] => 444
[tran_type] => expense
[date] => 2015-06-29
)
[3] => Array
(
[expense_id] => 10
[type] => frfrf
[mode] => rfr
[amount] => 1000
[tran_type] => income
[date] => 2015-06-29
)
)
[2015-06-01] => Array
(
[0] => Array
(
[expense_id] => 5
[type] => frfrf
[mode] => rfr
[amount] => 100
[tran_type] => expense
[date] => 2015-06-01
)
)
)
目前我正在使用foreach循环,是否有任何简单的方法来执行此操作
foreach ($d as $v) {
$d1[$v['date']][] = $v;
}
使用mysql检索数据,也可以接受mysql查询
答案 0 :(得分:1)
我只知道这种方式
$newArray = [];
foreach ($array as $subArray)
{
$newArray[$subArray['date']][] = $subArray;
}