Question

当用户点击“保存”按钮但我收到这些错误消息时，我正在尝试将表单中的数据插入到数据库中：

注意：未定义的索引：第5行的C：\ moodleFile \ server \ moodle \ local \ try \ process.php中的名称

注意：第6行的C：\ moodleFile \ server \ moodle \ local \ try \ process.php中的未定义索引：university_id

致命错误：在第15行的C：\ moodleFile \ server \ moodle \ local \ try \ process.php中的非对象上调用成员函数insert_record（）

这些是用户单击“保存”按钮时调用的文件代码：

<?php

global $DB;

$name = $_POST['name'];
$uni_id = $_POST['university_id'];

$record1 = new stdClass();
$record1->name  = $name;
$record1->displayorder = '10000';
$record2 = new stdClass();
$record2->name = $uni_id;
$record2->displayorder = '10000';
$records = array($record1, $record2);
$lastinsertid = $DB->insert_record('tbl_faculty', $records);

if(!$lastinsertid)
{
    echo "Could not insert";
}

?>

我是Moodle的新手可以有人帮帮我吗？感谢。

Answer 1

// Include config.php at the top of any user facing code.
require_once(dirname(dirname(dirname(__FILE__))) . '/config.php');

// Never trust input from the web, always use optional_param() or required_param() and specify the value type.
$name = optional_param('name', null, PARAM_TEXT);
$uni_id = optional_param('university_id', null, PARAM_TEXT);

$record1 = new stdClass();
$record1->name  = $name;
$record1->displayorder = '10000';

$record2 = new stdClass();
$record2->name = $uni_id;
$record2->displayorder = '10000';

// Insert one record at a time.
$lastinsertid1 = $DB->insert_record('faculty', $record1);
$lastinsertid2 = $DB->insert_record('faculty', $record2);

无法使用数据操作API-Moodle插入数据库

1 个答案: