Question

我正在尝试创建自己的自定义CMS，我可以注册用户并可以登录aswel，现在我正在尝试为用户角色创建一个函数，

文件：class.user.php

function getUserrole() {
    $username = htmlentities($_SESSION['user_session']);
    $stmt = $this->db->prepare('SELECT * FROM users WHERE user_name = :username');
    $stmt->bindParam(':user_name', $username);
    $stmt->execute();

    $row = $stmt->fetch(PDO::FETCH_ASSOC);

    $userrole = $row['user_role'];

    if($userrole == 3) {
        return $userrole = 3;
    }

    if($userrole == 2) {
        return $userrole = 2;
    }

    if($userrole == 1) {
        return $userrole = 1;
    }

    if($userrole == 0) {
        return $userrole = 0;
    }
}

文件：Home.php

<?php 
    $userrole = getUserrole();
    if($userrole == 1) {
        echo "Hi Admin";
    }

    else {
        echo "You are not a admin";
    }
?>

当我尝试这样做时，错误显示出来：

Fatal error: Call to undefined function getUserrole() in /Applications/MAMP/htdocs/test/home.php on line 24

我可以看到一些错误，我希望你们能帮助我在这里:)

整个class.user.php：

<?php
class USER
{
    private $db;

    function __construct($DB_con)
    {
        $this->db = $DB_con;
    }

    public function register($uname,$umail,$upass)
    {
        try
        {
            $new_password = password_hash($upass, PASSWORD_DEFAULT);

            $stmt = $this->db->prepare("INSERT INTO users(user_name,user_email,user_pass) 
                                                       VALUES(:uname, :umail, :upass)");

            $stmt->bindparam(":uname", $uname);
            $stmt->bindparam(":umail", $umail);
            $stmt->bindparam(":upass", $new_password);                                        

            $stmt->execute();   

            return $stmt;   
        }
        catch(PDOException $e)
        {
            echo $e->getMessage();
        }               
    }

    public function login($uname,$umail,$upass)
    {
        try
        {
            $stmt = $this->db->prepare("SELECT * FROM users WHERE user_name=:uname OR user_email=:umail LIMIT 1");
            $stmt->execute(array(':uname'=>$uname, ':umail'=>$umail));
            $userRow=$stmt->fetch(PDO::FETCH_ASSOC);
            if($stmt->rowCount() > 0)
            {
                if(password_verify($upass, $userRow['user_pass']))
                {
                    $_SESSION['user_session'] = $userRow['user_id'];
                    return true;
                }
                else
                {
                    return false;
                }
            }
        }
        catch(PDOException $e)
        {
            echo $e->getMessage();
        }
    }

    public function is_loggedin()
    {
        if(isset($_SESSION['user_session']))
        {
            return true;
        }
    }

    public function redirect($url)
    {
        header("Location: $url");
    }

    public function logout()
    {
        session_destroy();
        unset($_SESSION['user_session']);
        return true;
    }


function getUserrole() {
    $username = htmlentities($_SESSION['user_session']);
    $stmt = $this->db->prepare('SELECT * FROM users WHERE user_name = :username');
    $stmt->bindParam(':user_name', $username);
    $stmt->execute();

    $row = $stmt->fetch(PDO::FETCH_ASSOC);

    $userrole = $row['user_role'];

    if($userrole == 3) {
        return $userrole = 3;
    }

    if($userrole == 2) {
        return $userrole = 2;
    }

    if($userrole == 1) {
        return $userrole = 1;
    }

    if($userrole == 0) {
        return $userrole = 0;
    }
} 

}
?>

Answer 1

要求home.php中的类，init，然后调用函数

<?php 

require_once 'class.user.php';
$userClass = new USER(<yourdbcon>);

$userrole = $userClass->getUserrole();
if($userrole == 1) {
    echo "Hi Admin";
}

else {
    echo "You are not a admin";
}

＆GT;

PHP - UserRole - 功能 - OOP

1 个答案: