我有一个字符串：
[root@slave1 ~]# test -d /root/workspace/Servers || echo not found
[root@slave1 ~]# test -d /root/workspace/Servers || echo not found
not found
[root@slave1 ~]# test -d /root/workspace/Servers || echo not found
[root@slave1 ~]# test -d Desktp || echo not found
not found
我希望首先找不到not found的{{1}}这个词
如您所见，在此字符串中，将有2个匹配
我该怎么办？
答案 0 :(得分：1)
使用负面的背后隐藏。
"(?<!\\becho )not found(?=\\s|$)"
你可以在grep中使用相同的正则表达式。
grep -oP '(?<!\becho )not found(?=\s|$)' file
(?<!\becho ) - 不要期待echo<space>
not found(?=\s|$) - 但匹配所有not found字符串，后面必须跟一个空格或行尾。
答案 1 :(得分：0)
您可以将#include <stdafx.h>
#include <windows.h>
#include <iostream>
#include <fstream>
#include <codecvt> // for wstring_convert
#include <locale> // for codecvt_byname
using namespace std;
void BailOut(char *msg)
{
fprintf(stderr, "Exiting: %s\n", msg);
exit(1);
}
int main(int argc, char* argv[])
{
std::string codepage = ".1252";
if (argc > 1) {
std::string cpnum = argv[1];
codepage = "."+cpnum;
}
HANDLE clip;
string clip_text = "";
// exit if clipboard not available
if (!OpenClipboard(NULL))
BailOut("Can't open clipboard");
clip = GetClipboardData(CF_TEXT);
clip_text = (char*)clip;
CloseClipboard();
// create conversion routines
typedef std::codecvt_byname<wchar_t,char,std::mbstate_t> codecvt;
std::wstring_convert<codecvt> cp1252(new codecvt(".1252"));
std::wstring_convert<codecvt> outpage(new codecvt(codepage));
std::string OutFile = "#clip.txt"; // output file name
ofstream OutStream; // open an output stream
OutStream.open(OutFile, ios::out | ios::trunc);
// make sure file is successfully opened
if(!OutStream)
{
cout << "Error opening file " << OutFile << " for writing.\n";
return 1;
}
// convert to DOS/Win codepage number in "outpage"
OutStream << outpage.to_bytes(cp1252.from_bytes(clip_text)).c_str();
OutStream << endl;
OutStream.close(); // close output stream
return 0;
}
与启动锚点一起使用：
grep