SQL选择删除第一行的语句

Question

我在表格中有多行，我使用select语句来获取详细信息。

select * from pdetails where pcode='P000437' 

结果

我的查询打印3条记录，但我不想打印第一行。

是否有任何选项可以使用带有条件的select语句来计算和删除第一行。

Answer 1

尝试此查询

 SELECT * FROM (
    select ROW_NUMBER()OVER(ORDER BY id ASC) row,* from pdetails where pcode='P000437'
    )t
    WHERE row != 1;

Answer 2

您可以使用临时表

来获取此信息

IF OBJECT_ID('tempdb..#temp') IS NOT NULL
DROP TABLE #temp

SELECT *, ROW_NUMBER() over(order by id) as ROWID into #temp FROM pdetails 
WHERE pcode='P000437'

SELECT * FROM #temp WHERE ROWID != 1

Answer 3

试试这句话

 select * from pdetails where pcode='P000437' 
    order by id
    OFFSET 1 ROWS FETCH NEXT 2 ROWS ONLY

Answer 4

试试这个：

select * 
from pdetails 
where pcode= 'P000437' AND ID <> (SELECT MIN(ID)
                                 FROM pdetails
                                 WHERE pcode= 'P000437')

Answer 5

您可以使用ROW_NUMBER()排除第一行（基于Date）

像这样。

SELECT * FROM (
select ROW_NUMBER()OVER(ORDER BY Date ASC)rn,* from pdetails where pcode='P000437'
)t
WHERE rn != 1;