Question

我正在尝试使用条件检索CompanyOnCampus实体。它有一个组件类公司。映射是这样的：

<class name="entities.pp.Company" table="ie_company_info">
    <id column="company_id" name="id"/>
    <property column="company_name" name="name" type="string"/>
    <property column="company_short_name" name="shortName" type="string"/>
    <property column="company_description" name="description"    type="string"/>
</class>

<class name="entities.pp.CompanyOnCampus" table="c2ie_companies">
    <id column="c2ie_companie_id" name="id"/>
    <many-to-one column="c2ie_company_id" name="company"/>
    <many-to-one column="c2ie_institute_id" name="institute"/>
</class>

标准：

Criteria criteria = session.createCriteria(CompanyOnCampus.class);
criteria.add(Restrictions.eq("institute.instituteId", pUser.getInstituteInfo().getInstituteId()))
.add(Property.forName("company").getProperty("name").like(pSearchString+"%"));

OR

Criteria criteria = session.createCriteria(CompanyOnCampus.class);
criteria.add(Restrictions.eq("institute.instituteId", pUser.getInstituteInfo().getInstituteId()))
.add(Restrictions.ilike("company.name",pSearchString+"%"));

这里的结果是我得到了异常

org.hibernate.QueryException：无法解析类entities.pp.CompanyOnCampus的属性company.name ...

现在我尝试使用HQL：

String q = "FROM CompanyOnCampus company WHERE company.company.name LIKE :name AND company.institute.instituteId = :instiId";
Query hql = session.createQuery(q);
hql.setParameter("name", pSearchString+"%");
hql.setParameter("instiId", pUser.getInstituteInfo().getInstituteId());
List<CompanyOnCampus> companies = hql.list();

我在这里得到了结果。

Answer 1

创建company的别名将解决此问题。

Criteria criteria = session.createCriteria(CompanyOnCampus.class);
criteria.createAlias("company","company");

Answer 2

将公司的createAlias用作criteria.createAlias（＆＃34;公司＆＃34;，＆＃34;公司＆＃34;），即

Criteria criteria = session.createCriteria(CompanyOnCampus.class);
criteria.add(Restrictions.eq("institute.instituteId", pUser.getInstituteInfo().getInstituteId()))
.createAlias("company", "company")
.add(Restrictions.ilike("company.name", pSearchString+"%"));

做了这个伎俩。这表明，对于驻留在引用表中的字段/列，Criteria API需要提供显式别名。

谢谢！

Criteria抛出org.hibernate.QueryException：无法解析属性但HQL工作

2 个答案: