好的,所以我使用angular来将json保存到我的计算机上以重新创建github成绩簿。
我可以通过我的$ http请求获取数据但是为了爱我,我想要的只是计算标签问题的数量" Not Yet"。
这是javascript:
$http.get('/api/github/repos/issues/all_issues/00All.json')
.then(function(response) {
console.log(response.data[0]);
var counter = 0;
for(var index = 0; index < response.data.length; index++) {
if(response.data[index].labels[0].name == "Not Yet") {
counter++;
};
};
console.log(counter);
});
这是最新的尝试,我也尝试使用lodash来提前获得它:
$http.get('/api/github/repos/issues/all_issues/00All.json')
.then(function(response) {
console.log(response);
mile.notYet.width = _.forEach(response.data, function(n){
var counter = 0;
if(_.result(_.find(n.labels[0], 'name')) == "Not Yet") {
counter++;
}
console.log(counter);
counter = ((counter/10) * 100) + '%';
});
});
这是一些json数据:
[
{
"url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11",
"labels_url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11/labels{/name}",
"comments_url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11/comments",
"events_url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11/events",
"html_url": "https://github.com/TheIronYard--Orlando/2015--SUMMER--FEE/issues/11",
"id": 73013825,
"number": 11,
"title": "00 -- Brace Yourself -- BEN GRIFFITH",
"user": {
"login": "Epicurean306",
"id": 11682684,
"avatar_url": "https://avatars.githubusercontent.com/u/11682684?v=3",
"gravatar_id": "",
"url": "https://api.github.com/users/Epicurean306",
"html_url": "https://github.com/Epicurean306",
"followers_url": "https://api.github.com/users/Epicurean306/followers",
"following_url": "https://api.github.com/users/Epicurean306/following{/other_user}",
"gists_url": "https://api.github.com/users/Epicurean306/gists{/gist_id}",
"starred_url": "https://api.github.com/users/Epicurean306/starred{/owner}{/repo}",
"subscriptions_url": "https://api.github.com/users/Epicurean306/subscriptions",
"organizations_url": "https://api.github.com/users/Epicurean306/orgs",
"repos_url": "https://api.github.com/users/Epicurean306/repos",
"events_url": "https://api.github.com/users/Epicurean306/events{/privacy}",
"received_events_url": "https://api.github.com/users/Epicurean306/received_events",
"type": "User",
"site_admin": false
},
"labels": [
{
"url": "https://api.github.com/repos/TheIronYard--Orlando/2015--SUMMER--FEE/labels/Not%20Yet",
"name": "Not Yet",
"color": "e11d21"
}
],
正如你所看到的,labels属性是一个对象,嵌套在一个数组中,嵌套在一个对象中,嵌套在一个数组中,非常可爱。放置标签[0]每次都会给我带来错误,并且不会让我知道。任何人都可以告诉我在哪里搞砸了吗?谢谢!
答案 0 :(得分:1)
您不需要lodash执行任务
var cnt = response.data
.map(function(i) { return i.labels; })
// here we extract labels object only (and get an array of arrays of objects)
.map(function(i) { return i.filter(function(l) { return l.name == 'Not yet'; }).length; })
// then for every nested array we return a number of items with
// Not Yet names (and get an array of numbers)
.filter(function(c) { return c > 0; })
// then we filter issues that don't have one (and still get an array of numbers)
.length;
// and finally get length (which is a number)
答案 1 :(得分:1)
如果您需要一个包含lodash的解决方案,它比本机高阶函数更高效,那么您可以尝试以下解决方案:
var size = _(response.data)
.pluck('labels')
.flatten()
.where({ name: 'Not Yet' })
.size();
更新:
如果希望它更具可重用性,可以保存克隆链序列的引用,并为该克隆序列提供另一个数组。
var data1 = [/*array from data1*/];
var data2 = [/*array from data2*/];
var notYetSequence = _(data1)
.pluck('labels')
.flatten()
.where({ name: 'Not Yet' });
notYetSequence.size(); // returns data 1 count
notYetSequence.plant(data2).size(); // returns data 2 count
答案 2 :(得分:1)
作为比较,plain for循环看起来像:
git pull origin master
所以真的不是很多代码,for循环将与所有浏览器兼容(尽管使用xmlHTTPRequest意味着至少ed 3+)并且最快......当然未经测试。 ; - )