Question

我有一个MongoDB数据库，其中包含城市，州和邮政编码列表。我希望能够运行一个查询，根据用户输入检查每个字段，并且无法确定如何执行此操作。以下是db中的文档示例：

{"_id":"92199","city":"San Diego","state":"CA"}

以下是我用来返回该文件的路线：

    app.get('/city/:city', function(req, res){
        var query = City.aggregate( [
           { $group: { _id: "$zip", city: {"$first" : "$city"}, state: {"$first" : "$state"} } },
           { $match: {"city": new RegExp(req.params.city, "i")} }
        ]);
        query.exec(function(err, city){
            if(err){
                console.log(err);
                return res.send(err);
            }
            console.log(city);
            res.json(city);
        });
    });

问题在于，如果我查询San Diego，CA，查询将失败，因为它只搜索城市。如何查询city，state和zip（_id）以便仍然返回一个值？

Answer 1

如果有人有兴趣，我最终会为我工作。可能会重构，但这有效：

    app.get('/city/:city', function(req, res){

        var location = req.params.city.replace(",", "");
        location = toTitleCase(location);
        location = location.split(" ");

        for (var i = 0; i < location.length; i++) {
            if(location[i].length == 2){
                var state = location[i].toUpperCase();
                var stateIndex = i;
            }
            if(!isNaN(parseFloat(location[i])) && isFinite(location[i])){
                var zip = location[i];
                var zipIndex = i;
            }               
        }

        if(zipIndex){
            location.splice(zipIndex, 1);
        }
        if(stateIndex){
            location.splice(stateIndex, 1);
        }

        location = location.join(" ");

        if(state && zip){
             var query = City.find({
            $and: [
                { $and: [{"state": state}, {"city": new RegExp(location, "i")}] },
                { "zip" : zip }
            ]
        });
        }else if(zip){
            var query = City.find({
                $or : [{"city": new RegExp(location, "i")}, {"zip" : zip}]
            });
        }else if(state){
            var query = City.find({
                 $and: [{"state": state}, {"city": new RegExp(location, "i")}]
            });
        }
        else{
             var query = City.find({
                "city": new RegExp(location, "i")
            });
        }
        query.exec(function(err, city){
            if(err){
                console.log(err);
                return res.send(err);
            }
            res.json(city);
        });
    });

感谢@Semicolon对评论的帮助。

NodeJS，Mongoose - 查询城市，州或邮政编码

1 个答案: