我有一些我要解析的perfmon（Windows性能日志数据）数据。
通常一组列名如下所示：
> colnames(p)
[1] "Time"
[2] "\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Queue Length"
[3] "\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Read Queue Length"
[4] "\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Write Queue Length"
[5] "\\\\testdb1\\Processor(_Total)\\% Processor Time"
[6] "\\\\testdb1\\System\\Processes"
[7] "\\\\testdb1\\System\\Processor Queue Length"
我将这些数据输入R的方式是：
p <- read.csv("r-perfmon.csv",stringsAsFactors = FALSE, check.names = FALSE)
以下是一些示例数据
> head(p)
Time \\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Queue Length
1 04/15/2013 00:00:19.279 0.040037563
2 04/15/2013 00:00:34.279 0.009740260
3 04/15/2013 00:00:49.275 0.011009828
4 04/15/2013 00:01:04.284 0.006016244
5 04/15/2013 00:01:19.279 0.015125328
6 04/15/2013 00:01:34.275 0.002814141
\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Read Queue Length
1 0.001421333
2 0.000000000
3 0.000206726
4 0.000000000
5 0.001894000
6 0.000000000
\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Write Queue Length
1 0.038616230
2 0.009740260
3 0.010803102
4 0.006016244
5 0.013231327
6 0.002814141
\\\\testdb1\\Processor(_Total)\\% Processor Time \\\\testdb1\\System\\Processes
1 29.569339 86
2 10.856994 86
3 7.733924 81
4 1.910202 81
5 6.164864 81
6 1.351883 81
\\\\testdb1\\System\\Processor Queue Length
1 0
2 0
3 0
4 0
5 0
6 0
我希望能够解析列名，然后融化数据。
因此，如果我们以一列数据为例
> example <- p[2]
> head(example)
\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Queue Length
1 0.040037563
2 0.009740260
3 0.011009828
4 0.006016244
5 0.015125328
6 0.002814141
我希望它看起来像这样
Time, MachineName, Object, Counter, InstanceName, Value
04/15/2013 00:00:19.279, testdb1, PhysicalDisk, Avg. Disk Queue Length, 0 C:, 0.040037563
04/15/2013 00:00:34.279, testdb1, PhysicalDisk, Avg. Disk Queue Length, 0 C:, 0.009740260
04/15/2013 00:00:49.275, testdb1, PhysicalDisk, Avg. Disk Queue Length, 0 C:, 0.011009828
编辑：根据要求输入我的数据头
structure(list(`(PDH-CSV 4.0) (GMT Daylight Time)(-60)` = c("04/15/2013 00:00:19.279",
"04/15/2013 00:00:34.279", "04/15/2013 00:00:49.275", "04/15/2013 00:01:04.284",
"04/15/2013 00:01:19.279", "04/15/2013 00:01:34.275"), `\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Queue Length` = c(0.040037563,
0.00974026, 0.011009828, 0.006016244, 0.015125328, 0.002814141
), `\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Read Queue Length` = c(0.001421333,
0, 0.000206726, 0, 0.001894, 0), `\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Write Queue Length` = c(0.03861623,
0.00974026, 0.010803102, 0.006016244, 0.013231327, 0.002814141
), `\\\\testdb1\\Processor(_Total)\\% Processor Time` = c(29.56933862,
10.85699395, 7.733924001, 1.910202013, 6.164864178, 1.351882837
), `\\\\testdb1\\System\\Processes` = c(86L, 86L, 81L, 81L, 81L,
81L), `\\\\testdb1\\System\\Processor Queue Length` = c(0L, 0L, 0L,
0L, 0L, 0L)), .Names = c("(PDH-CSV 4.0) (GMT Daylight Time)(-60)",
"\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Queue Length", "\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Read Queue Length",
"\\\\testdb1\\PhysicalDisk(0 C:)\\Avg. Disk Write Queue Length",
"\\\\testdb1\\Processor(_Total)\\% Processor Time", "\\\\testdb1\\System\\Processes",
"\\\\testdb1\\System\\Processor Queue Length"), row.names = c(NA,
6L), class = "data.frame")
答案 0 :(得分：1)
有点难以知道您的最终数据应该是什么样子，就像每个列名称被反斜杠或括号分开一样，根据输入列，结果中会得到不同数量的列。
所以我将每列拆分成一个单独的列表元素。如果dput中的data.frame被称为d
# Look at second column - then all you need to do is tweak the names
s <- strsplit(colnames(d)[2], "\\\\|\\)|\\(")[[1]]
data.frame(time = d[[1]], t(s[nzchar(s)]), value=d[[2]])
time X1 X2 X3 X4 value
1 04/15/2013 00:00:19.279 testdb1 PhysicalDisk 0 C: Avg. Disk Queue Length 0.040037563
2 04/15/2013 00:00:34.279 testdb1 PhysicalDisk 0 C: Avg. Disk Queue Length 0.009740260
3 04/15/2013 00:00:49.275 testdb1 PhysicalDisk 0 C: Avg. Disk Queue Length 0.011009828
4 04/15/2013 00:01:04.284 testdb1 PhysicalDisk 0 C: Avg. Disk Queue Length 0.006016244
5 04/15/2013 00:01:19.279 testdb1 PhysicalDisk 0 C: Avg. Disk Queue Length 0.015125328
6 04/15/2013 00:01:34.275 testdb1 PhysicalDisk 0 C: Avg. Disk Queue Length 0.002814141
strsplit将每个字符串拆分为\\或(或) - 请注意，在R中，这些字符串需要使用前导\\进行转义。这导致一些空字符串被nzchar函数删除（如果零长度则返回FALSE）
# Apply it over all variables
lapply(seq_along(colnames(d))[-1], function(i) {
s <- strsplit(colnames(d)[[i]], "\\\\|\\)|\\(")[[1]]
data.frame(time = d[[1]], t(s[nzchar(s)]), value=d[[i]])
})
同样，您需要重命名列。