// Queries atlatlsoftware.com and returns the site in json data format, using YQL
$.ajax({
url: "https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20html%20where%20url%3D%22http%3A%2F%2Fatlatlsoftware.com%22%20and%0A%20%20%20%20%20%20xpath%3D'%2F%2F*%5B%40id%3D%22desktop-footer%22%5D%2Fdiv%5B3%5D%2Fdiv%2Ftable%2Ftbody%2Ftr%5B2%5D%2Ftd%5B1%5D'&format=json&diagnostics=true&callback=?",
dataType: 'jsonp',
// upon success, logs the data as "response"
success: function (response) {
// simply following the json data path and assigning it to a variable
var address = response.query.results.td.div[1].content;
var phone = response.query.results.td.div[2];
var email = response.query.results.td.div[3];
// var tweet = response.query.results;
// appends the variable to the html
$(".address").html(address);
$(".phone").html(phone);
$(".email").html(email);
console.log(address);
console.log(phone);
console.log(email);
// console.log(tweet);
}
});
上面的脚本从网站上提取地址,电子邮件和电话号码。我怎样才能简单地将这些数据保存到文本文件中?
我尝试this但没有使用点击事件
答案 0 :(得分:0)
据我所知,Firefox和Chrome都不要求在链接文章的saveTextAsFile
中运行代码以响应用户事件。 (这是可怕的,几乎肯定是一个错误。)所以只需调整示例,以便从saveTextAsFile
完成处理程序中调用ajax
。