Question

我正在尝试创建自定义弹出式提醒。将它添加到我的视图并为其设置动画效果都很好，但是在触发它时加载需要一段时间。

这就是我创建视图的方式。

@implementation SAActionAlertView

-(id)initWithTitle:(NSString *)title view:(UIView *)view;
{
    self = [super init];
    if (self){
        self = [[[NSBundle mainBundle]loadNibNamed:@"ActionAlertView" owner:self options:nil]objectAtIndex:0];
        self.actionAlertText.text = title;
        self.view = view;
    }
    return self;
}

-(void)animate;
{
    [self.view addSubview:self];
    self.center = self.superview.center;
    self.transform = CGAffineTransformMakeScale(0.01, 0.01);
    [UIView animateWithDuration:0.3 delay:0 options:UIViewAnimationOptionCurveEaseOut animations:^{
        self.transform = CGAffineTransformIdentity;
    } completion:^(BOOL finished){
        __block CGRect queueFrame = self.frame;
        __block int queueY = queueFrame.origin.y;
        [UIView animateWithDuration:.3 delay:.5 options:UIViewAnimationOptionCurveEaseOut animations:^{
            queueY += 50;
            self.frame = queueFrame;
            self.alpha = .3;
        } completion:^(BOOL finished) {
            [self removeFromSuperview];
        }];
    }];
}

@end

这就是我在主视图控制器上呈现它的方式。

#pragma mark - Notification Center

-(void)trackQueued:(NSNotification *)notification
{
    SAActionAlertView *actionAlert = [[SAActionAlertView alloc]initWithTitle:@"Track Queued" view:self.view];
       [actionAlert animate];
}

视图显示和动画需要太长时间。我希望在触发事件时弹出即时。有关正确实现这一目标的任何想法？

Answer 1

由于您在通知后执行动画，我假设您没有在主线程上运行。你应该。如果您在主线程以外的任何线程上执行UI更改，则无法确定它们何时实际反映在设备上的实际屏幕上。

- (void) trackQueued:(NSNotification *)notification {
    dispatch_async(dispatch_get_main_queue(), ^{
        SAActionAlertView *actionAlert = [[SAActionAlertView alloc]initWithTitle:@"Track Queued" view:self.view];
        [actionAlert animate];
    });
}

创建自定义警报弹出加载速度太慢

1 个答案: