Question

我正在尝试在Flash AS3中制作一个RPG风格的游戏。当他击中树木和建筑物等物体时，我试图让我的角色停下来。有没有办法可以将多个对象链接在一起，并让代码说出像 object1 ， object2 和 object3 这样的内容将其命名为 multipleobjects ＆＃39 ;?我已经设置了代码，以便角色停在一棵树上，但我不确定如何/如果你可以组合对象，这样他就不会同时经历多个。非常感谢先进！对象： manmc（我的角色），treer1_MC（第一棵树）treer2_MC（第二棵树）等等

import flash.events.KeyboardEvent;
import flash.ui.Keyboard;
import flash.display.MovieClip;
import flash.events.Event;
import flash.display.Stage;

manmc.gotoAndStop ("Stand Front Frame");

var rightPressed:Boolean = new Boolean(false);
var leftPressed:Boolean = new Boolean(false);
var upPressed:Boolean = new Boolean(false);
var downPressed:Boolean = new Boolean(false);
var manSpeed:Number = 3;

stage.addEventListener(KeyboardEvent.KEY_DOWN, keyDownHandler);
stage.addEventListener(KeyboardEvent.KEY_UP, keyUpHandler);
stage.addEventListener(Event.ENTER_FRAME, gameLoop);

function keyDownHandler (keyEvent:KeyboardEvent):void
{
    if(keyEvent.keyCode == Keyboard.RIGHT)
    {
        rightPressed = true;
    }
    else if(keyEvent.keyCode == Keyboard.LEFT)
    {
        leftPressed = true;
    }
    else if(keyEvent.keyCode == Keyboard.UP)
    {
        upPressed = true;
    }
    else if(keyEvent.keyCode == Keyboard.DOWN)
    {
        downPressed = true;
    }
}

function keyUpHandler (keyEvent:KeyboardEvent):void
{
    if(keyEvent.keyCode == Keyboard.RIGHT)
    {
        rightPressed = false;
        manmc.gotoAndStop("Stand Right Frame");
    }
    else if(keyEvent.keyCode == Keyboard.LEFT)
    {
        leftPressed = false;
        manmc.gotoAndStop("Stand Left Frame");
    }
    else if(keyEvent.keyCode == Keyboard.UP)
    {
        upPressed = false;
        manmc.gotoAndStop("Stand Back Frame");
    }
    else if(keyEvent.keyCode == Keyboard.DOWN)
    {
        downPressed = false;
        manmc.gotoAndStop("Stand Front Frame");
    }
}

function gameLoop(loopEvent:Event):void
{
    if(rightPressed)
    {
        if(manmc.x < 1050)
        {
            manmc.x += manSpeed;
        }
        manmc.gotoAndStop("Walk Right Frame");

        if (manmc.hitTestObject(treer1_MC))
    {
        trace("leftHit");
        manmc.x -= 3;
    }
}
    else if(leftPressed)
    {
        if (manmc.x > 145)
        {
            manmc.x -= manSpeed;
        }
        manmc.gotoAndStop("Walk Left Frame");

        if (manmc.hitTestObject(treer1_MC))
    {
        trace("rightHit");
        manmc.x += 3;
    }
} 
      else if(downPressed)
{
    if(manmc.y < 780)
    {
    manmc.y += manSpeed;
    }
    manmc.gotoAndStop("Walk Front Frame");

    if (manmc.hitTestObject(treer1_MC))
    {
        trace("downHit");
        manmc.y -= 3;
    }
}
        else if(upPressed)
{
    if(manmc.y > 145)
    {
    manmc.y -= manSpeed;
    }
    manmc.gotoAndStop("Walk Back Frame");

    if (manmc.hitTestObject(treer1_MC))
    {
        trace("upHit");
        manmc.y += 3;
    }
}
}

Answer 1

使用数组来跟踪多个对象。

然后使用循环迭代数组中作为单个对象的所有元素，而不是操纵单个对象。

将多个对象链接到一个编码名称

1 个答案: