Question

我完全不确定自己哪里出错了，令我惊讶的是我无法理解，所以任何建议都会非常感激。

我有两个模特userr（招聘人员）＆amp;反馈者（招聘人员反馈）
[用户模型] userr has_many :feedbackr
[反馈者模型] belongs_to :userr
[架构]我已将userr_id列添加到表反馈器
[feedbackrs_controller]我已将:userr_id添加到feedbackr_params

问题是，当我创建一个反馈评论作为招聘人员和＆amp;走进入我的控制台并输入Feebackr.find(4)（最后创建的反馈）userr_id显示nil - 它假设显示创建了a的用户（招募者）的id 反馈 - 我不确定为什么它显示nil，因为我的协会似乎都正确 -

任何建议都会非常感激 - 我的文件如下 -

控制台

2.1.2 :055 > ap Feedbackr.find(4)
  Feedbackr Load (0.3ms)  SELECT  "feedbackrs".* FROM "feedbackrs"  WHERE "feedbackrs"."id" = ? LIMIT 1  [["id", 4]]
#<Feedbackr:0x007fd89136e018> {
                       :id => 4,
                    :email => "richill@gmail.com",
               :created_at => Sun, 28 Jun 2015 00:29:52 UTC +00:00,
               :updated_at => Sun, 28 Jun 2015 00:29:52 UTC +00:00,
    :category_feedbackr_id => 6,
                  :content => "feedback1",
                 :userr_id => nil
}
 => nil 
2.1.2 :056 >

模式

ActiveRecord::Schema.define(version: 20150627235330) do

  create_table "feedbackrs", force: true do |t|
    t.string   "email"
    t.datetime "created_at"
    t.datetime "updated_at"
    t.integer  "category_feedbackr_id"
    t.text     "content"
    t.integer  "userr_id"
  end

  create_table "userrs", force: true do |t|
    t.string   "email",                    default: "", null: false
    t.string   "encrypted_password",       default: "", null: false
    t.string   "reset_password_token"
    t.datetime "reset_password_sent_at"
    t.datetime "remember_created_at"
    t.integer  "sign_in_count",            default: 0,  null: false
    t.datetime "current_sign_in_at"
    t.datetime "last_sign_in_at"
    t.string   "current_sign_in_ip"
    t.string   "last_sign_in_ip"
    t.datetime "created_at"
    t.datetime "updated_at"
    t.string   "confirmation_token"
    t.datetime "confirmed_at"
    t.datetime "confirmation_sent_at"
    t.string   "unconfirmed_email"
  end

  add_index "userrs", ["confirmation_token"], name: "index_userrs_on_confirmation_token", unique: true
  add_index "userrs", ["email"], name: "index_userrs_on_email", unique: true
  add_index "userrs", ["reset_password_token"], name: "index_userrs_on_reset_password_token", unique: true

end

feedbackr.rb

class Feedbackr < ActiveRecord::Base
  belongs_to :userr
end

userr.rb

class Userr < ActiveRecord::Base
  # Include default devise modules. Others available are:
  # :confirmable, :lockable, :timeoutable and :omniauthable
  devise :database_authenticatable, :registerable,
         :recoverable, :rememberable, :trackable, :validatable, :confirmable

  has_many :feedbackrs
end

feedbackr_controller.rb

class FeedbackrsController < ApplicationController
  respond_to :html, :xml, :json
  before_action :set_feedbackr, only: [:show, :edit, :update, :destroy]

  def index
    @feedbackrs = Feedbackr.all.order("created_at DESC")
    respond_with(@feedbackrs)
  end

  def show
    respond_with(@feedbackr)
  end

  def new
    @feedbackr = Feedbackr.new
    respond_with(@feedbackr)
  end

  def edit
  end

  def create
    @feedbackr = Feedbackr.new(feedbackr_params)
    respond_to do |format|
      if @feedbackr.save
        format.html { redirect_to dashboard_path, :notice => 'Thank you for your feedback' }
        format.xml  { render :xml => @feedbackr, :status => :created, :location => [@feedbackr] }
      else
        format.html { render :action => "new" }
        format.xml  { render :xml => @feedbackr.errors, :status => :unprocessable_entity }
      end  
    end
  end

  def update
    ...
  end

  def destroy
    ...
  end

  private
    def set_feedbackr
      @feedbackr = Feedbackr.find(params[:id])
    end

    def feedbackr_params
      params.require(:feedbackr).permit(:email, :category_feedbackr_id, :content, :userr_id)
    end
end

视图/ feedbackrs / _form.html.erb

<%= simple_form_for(@feedbackr) do |f| %>
  <%= f.error_notification %>

  <div class="form-inputs">
    <%= f.input_field :email, label: 'email address', value: current_userr.email %>
    <%= f.association :category_feedbackr, as: :radio_buttons, label: 'How likely are you to recommend us?' %>
    <%= f.input :content, label: 'What is the primary reason for your score?'%>
  </div>

  <div class="form-actions">
    <%= f.button :submit, 'Provide Feedback' %>
  </div>
<% end %>
<div><%= render 'shared/footer' %></div>

Answer 1

您是否要将current_user设为userr？

def create
    @feedbackr = Feedbackr.new(feedbackr_params)
    @feedbackr.userr = current_user # And make sure the user is authenticated (though you probably did that in your ApplicationController ?)
    respond_to do |format|
      if @feedbackr.save
        format.html { redirect_to dashboard_path, :notice => 'Thank you for your feedback' }
        format.xml  { render :xml => @feedbackr, :status => :created, :location => [@feedbackr] }
      else
        format.html { render :action => "new" }
        format.xml  { render :xml => @feedbackr.errors, :status => :unprocessable_entity }
      end  
    end
  end

Answer 2

在@feedbackr.userr = current_user文件中分配feedbackrs_controller.rb会自动生成user_id字段。目前，您在生成feebackr时没有向user_id分配任何内容，因此您的userr_id = nil也是如此。

Rails关联 - user_id表示nil Rails 4

2 个答案: