Question

我正在尝试构建一个抽奖系统，允许您选择参与者，然后将其打印到屏幕上。我想让它与python3和python2交叉兼容。我输入有问题。请求您输入参与者姓名的输入向下输入错误：

Traceback (most recent call last): File "employee-raffle.py", line 20, in <module> participant_list.append(input("Enter person " + str(len(participant_list) + 1) + ": ")) File "<string>", line 1, in <module> NameError: name 'test' is not defined

来自代码：

# Import modules
import time
import random

print("Welcome to the raffle ")
participants = 0

# Checks how many people are participating in the raffle
while True:
    try:
        participants = int(input("\nHow many people are there in the raffle? \n"))
        break
    except:
        print("Invalid option")
        continue

# Creates a list and asks user to input the names of everyone
participant_list = []
while participants > len(participant_list):
    participant_list.append(input("Enter person " + str(len(participant_list) + 1) + ": "))

# Chooses a random person
random_participant = participant_list[random.randint(0,len(participant_list ) - 1)]

# Prints the person to the screen
print("AND THE WINNER IS:")
print("3")
time.sleep(1)
print("2")
time.sleep(1)
print("1")
time.sleep(1)
print(random_participant)

它似乎在python 3中运行良好。我真的希望它能与两者兼容，因为我正在努力学习如何使事物交叉兼容，因为在我看来它是一个重要的编程实践。

Answer 1

This blog有一些使python文件兼容python 3和2的例子。

他提到的输入的一个特定示例是：

def printme(s):
    sys.stdout.write(str(s))

def get_input(prompt):
    if sys.hexversion > 0x03000000:
        return input(prompt)
    else:
        return raw_input(prompt)

使某些东西与python 3和2兼容

1 个答案: