字符串未分配给列表视图项

时间:2015-06-27 13:37:32

标签: java android android-layout android-listview android-listfragment

我正在尝试使用strings.xml文件中的一些字符串作为列表视图的项目名称,但在部署期间,我的应用程序将无法运行。我已经在互联网的许多方面查看了相关的教程,但所有这些都只显示了硬编码的字符串。有谁知道我的代码有什么问题,以及如何使用字符串修复它而不是硬编码?

    public class FragmentLineChooserList extends android.support.v4.app.Fragment {

        ListView list_linechooser;

        String[] listContent = {
                getResources().getString(R.string.item_0),
                getResources().getString(R.string.item_1),
                getResources().getString(R.string.item_2)
        };

        private boolean mTwoPane;

        public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState){
            View v = inflater.inflate(R.layout.fragment_line_chooser_list, container, false);

            list_linechooser = (ListView)v.findViewById(R.id.list_linechooser);
        MyColoringAdapter adapter = new MyColoringAdapter(getActivity(),listContent);
        list_linechooser.setAdapter(adapter);
       );

        return v;
    }

    private class MyColoringAdapter extends ArrayAdapter<String> {
        private final Context context;
        private final String[] values;

        public MyColoringAdapter(Context context, String[] values) {
            super(context, R.layout.list_item, values);
            this.context = context;
            this.values = values;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent) {
            LayoutInflater inflater = (LayoutInflater) context
                    .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            View rowView = inflater.inflate(R.layout.list_item, parent, false);
            TextView textView = (TextView) rowView.findViewById(R.id.list_item);
            textView.setText(values[position]);
            int textColorId = R.color.white; // Default color
            switch (position) {
                case 0:
                    textColorId = R.color.red; break;
                case 1:
                    textColorId = R.color.yellow; break;
                case 2:
                    textColorId = R.color.green; break;
            }
            textView.setTextColor(getResources().getColor(textColorId));
            return rowView;
        }
    }
}

1 个答案:

答案 0 :(得分:2)

喜欢

  String[] listContent = {
            getActivity().getResources().getString(R.string.item_0),
            getActivity().getResources().getString(R.string.item_1),
            getActivity().getResources().getString(R.string.item_2)
    };
<{1>}

下的