我有这样的日期选择器,根据图像选择的当前日期是02/06/2015,如果我点击" +1天"然后它应该通过错误"日期不可用",因为03/06/2015不可用或禁用。
以前有人这样做过,请建议回答。
答案 0 :(得分:1)
我刚刚做了一个例子。我必须覆盖一些方法,做一些技巧。希望这有帮助。下面的演示。
$(function() {
var beforeShowFunction = function(input, inst) {
setTimeout(function() {
var buttonPane = $(input).datepicker("widget")
.find(".ui-datepicker-buttonpane");
var btn = $('<button class="ui-datepicker-current ui-state-default ui-priority-secondary ui-corner-all" type="button">+</button>');
btn.bind("click", function(e) {
if ($(input).datepicker('getDate') == null)
return;
var currentDate = new Date($(input).datepicker("getDate"));
var newDate = new Date(currentDate.setDate(currentDate.getDate() + 1));
$(input).datepicker("setDate", newDate);
currentDate = new Date($(input).datepicker("getDate"));
if (currentDate.getDate() != newDate.getDate()) {
alert('Unavailabled!');
}
$(input).datepicker("hide");
$(input).datepicker("show");
});
btn.appendTo(buttonPane);
var btnMinus = $('<button class="ui-datepicker-current ui-state-default ui-priority-secondary ui-corner-all" type="button">-</button>');
btnMinus.bind("click", function(e) {
if ($(input).datepicker('getDate') == null)
return;
var currentDate = new Date($(input).datepicker("getDate"));
var newDate = new Date(currentDate.setDate(currentDate.getDate() - 1));
$(input).datepicker("setDate", newDate);
currentDate = new Date($(input).datepicker("getDate"));
if (currentDate.getDate() != newDate.getDate()) {
alert('Unavailabled!');
}
$(input).datepicker("hide");
// force call show to see +, - buttons
$(input).datepicker("show");
});
btnMinus.appendTo(buttonPane);
}, 1);
};
$("#datepicker").datepicker({
minDate: -20,
maxDate: "+1M +10D",
showButtonPanel: true,
beforeShow: beforeShowFunction,
});
// Below fix today button
jQuery.datepicker._gotoToday = function(id) {
var target = jQuery(id);
var inst = this._getInst(target[0]);
if (this._get(inst, 'gotoCurrent') && inst.currentDay) {
inst.selectedDay = inst.currentDay;
inst.drawMonth = inst.selectedMonth = inst.currentMonth;
inst.drawYear = inst.selectedYear = inst.currentYear;
} else {
var date = new Date();
inst.selectedDay = date.getDate();
inst.drawMonth = inst.selectedMonth = date.getMonth();
inst.drawYear = inst.selectedYear = date.getFullYear();
this._setDateDatepicker(target, date);
this._selectDate(id, this._getDateDatepicker(target));
}
this._notifyChange(inst);
this._adjustDate(target);
// force call show to see +, - buttons
$('#datepicker').datepicker("show");
};
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<link href="https://code.jquery.com/ui/1.11.3/themes/smoothness/jquery-ui.css" rel="stylesheet" />
<script src="https://code.jquery.com/ui/1.11.1/jquery-ui.min.js"></script>
<input type="text" id="datepicker" />
<br />
答案 1 :(得分:-1)
您可以检查输入日期是否为有效日期,例如:
DateTime d = new DateTime();
DateTime.TryParse("33-01-2014", out d);
你也可以加一天
d.AddDays(1);
并检查月份是否发生变化或其他......